Exercise 15, § 1 Algebra, VI, p. 32 Show that ∣x+−y+∣+∣x−−y−∣=∣x−y∣ |x^+ - y^+| + |x^- - y^-| = |x - y| ∣x+−y+∣+∣x−−y−∣=∣x−y∣ in a lattice ordered group (notice that x−y≤∣x−y∣x - y \leq |x - y|x−y≤∣x−y∣ and ∣x∣−∣y∣≤∣x−y∣|x| - |y| \leq |x - y|∣x∣−∣y∣≤∣x−y∣). Solution No solution has been written yet.