Bourbaki

Example

Tag 0164, permanent. Cite it as [Bourbaki, Tag 0164].

Lie Groups and Lie Algebras, chapter VIII, § 9. The formula of Hermann Weyl

We return to the Example of no. 1. Let λ=(n/2)α,μ=(p/2)α\lambda = (n/2)\alpha , \mu= (p/2)\alpha, ν=(q/2)α\nu = (q/2)\alpha with n≥pn\geq p. We have

m(λ,μ,ν)=P(n2α+α2+p2α+α2−q2α−α) m(\lambda , \mu, \nu ) =\mathfrak{P}(\frac{n}{2}\alpha +\frac{\alpha}{2}+\frac{p}{2}\alpha +\frac{\alpha}{2}-\frac{q}{2}\alpha -\alpha )
−P(n2α+α2−p2α−α2−q2α−α) -\mathfrak{P}(\frac{n}{2}\alpha +\frac{\alpha}{2}-\frac{p}{2}\alpha -\frac{\alpha}{2}-\frac{q}{2}\alpha -\alpha )
−P(−n2α−α2+p2α+α2−q2α−α) -\mathfrak{P}(-\frac{n}{2}\alpha -\frac{\alpha}{2}+\frac{p}{2}\alpha +\frac{\alpha}{2}-\frac{q}{2}\alpha -\alpha )
+P(−n2α−α2−p2α−α2−q2α−α) +\mathfrak{P}(-\frac{n}{2}\alpha -\frac{\alpha}{2}-\frac{p}{2}\alpha -\frac{\alpha}{2}-\frac{q}{2}\alpha -\alpha )
=P(n+p−q2α)−P(n−p−q−22α) =\mathfrak{P}(\frac{n + p-q}{2}\alpha )-\mathfrak{P}(\frac{n-p-q- 2}{2}\alpha )

This is zero if n+p+qn+p+q is not divisible by 2, or if q≥n+pq\geq n+p. If

q=n+p−2r q=n+p-2r

with rr an integer ≥0\geq 0, we have

m(λ,μ,ν)=P(rα)−P((r−p−1)α) m(\lambda , \mu, \nu ) =\mathfrak{P}(r\alpha )-\mathfrak{P}((r-p-1)\alpha )

hence m(λ,μ,ν)=1m(\lambda , \mu, \nu ) = 1 if r≤pr\leq p and m(λ,μ,ν)=0m(\lambda , \mu, \nu ) = 0 if r>pr > p. Finally, the g\mathfrak{g}-module V(n)⊗V(p)V(n)\otimes V(p) is isomorphic to

V(n+p)⊕V(n+p−2)⊕V(n+p−4)⊕⋯⊕V(n−p) V(n+p)\oplus V(n+p-2)\oplus V(n+p-4)\oplus \cdots \oplus V(n-p)

(Clebsch-Gordan formula).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

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Cites

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Transcribed from the printed volume. Not translated.