We return to the Example of no. 1. Let λ=(n/2)α,μ=(p/2)α, ν=(q/2)α with n≥p. We have
m(λ,μ,ν)=P(2nα+2α+2pα+2α−2qα−α)
−P(2nα+2α−2pα−2α−2qα−α)
−P(−2nα−2α+2pα+2α−2qα−α)
+P(−2nα−2α−2pα−2α−2qα−α)
=P(2n+p−qα)−P(2n−p−q−2α)
This is zero if n+p+q is not divisible by 2, or if q≥n+p. If
q=n+p−2r
with r an integer ≥0, we have
m(λ,μ,ν)=P(rα)−P((r−p−1)α)
hence m(λ,μ,ν)=1 if r≤p and m(λ,μ,ν)=0 if r>p. Finally, the g-module V(n)⊗V(p) is isomorphic to
V(n+p)⊕V(n+p−2)⊕V(n+p−4)⊕⋯⊕V(n−p)
(Clebsch-Gordan formula).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
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