Bourbaki

Exercise 3, § 1

Tag 03G3, permanent. Cite it as [Bourbaki, Tag 03G3].

Theory of Sets, I, 56

Let AA be a term or a relation in a theory T\mathscr{T}. Show that every specific sign, if there is any, is followed by □\square, or τ\tau, or a letter, or a substantific sign.

Solution

This solution was written by laguna-s-2.1-free and judged by a machine. It is not Bourbaki's and it has not been checked by a person.

Let us proceed by induction on the length of a formative construction of T\mathscr{T} that produces the term or relation AA. Suppose that every assembly in the formative construction preceding AA satisfies the required condition: every specific sign (if present) is followed by □\square, τ\tau, a letter, or a substantific sign. We verify that AA also satisfies the condition.

- Condition (a): AA is a single letter. The statement holds vacuously since there are no specific signs.

- Condition (b): A=¬BA = \neg B where BB is a relation. The specific signs in AA are those in BB, which satisfy the condition by hypothesis. Hence AA does too.

- Condition (c): A=∨BCA = \vee BC with BB and CC relations. The specific signs in AA are inherited from BB and CC, which satisfy the condition.

- Condition (d): A=τx(B)A = \tau_x(B) where BB is a relation. By definition, τx(B)\tau_x(B) is τ\tau followed by the assembly BB with each occurrence of xx replaced by □\square and linked to τ\tau. The τ\tau here is a logical sign. The next signs after any specific sign in BB are either unchanged (and thus satisfy the hypothesis) or τ\tau followed by □\square (in the case where a specific sign in BB was followed by xx, now replaced by □\square). Thus τx(B)\tau_x(B) satisfies the condition.

- Condition (e): A=sA1A2…AnA = sA_1A_2 \dots A_n, where ss is a specific sign and A1,…,AnA_1, \dots, A_n are terms. Since AA is a term or relation, ss must be a substantific sign (if AA is a term) or a relational sign (if AA is a relation). The first sign after ss is the first sign of A1A_1. Each AiA_i is a term, hence of first species, so A1A_1 begins with τ\tau, a substantific sign, or is a single letter. These are allowed after ss, as □\square, τ\tau, or a letter. Remaining specific signs in AA come from the AiA_i, which satisfy the condition by hypothesis. Thus AA satisfies the condition.

By induction, every term or relation AA has the desired property.

Cited by

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Cites

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Transcribed from the printed volume. Not translated.