Bourbaki

Exercise 5, § 4

Tag 03IF, permanent. Cite it as [Bourbaki, Tag 03IF].

Theory of Sets, II, 126

Let (Gι)ι∈I(\mathrm{G}_\iota)_{\iota \in \mathrm{I}} be a family of graphs and let H be a graph. Show that

(⋃ι∈IGι)∘H=⋃ι∈I(Gι∘H)andH∘(⋃ι∈IGι)=⋃ι∈I(H∘Gι).\left( \bigcup_{\iota \in \mathrm{I}} \mathrm{G}_\iota \right) \circ \mathrm{H} = \bigcup_{\iota \in \mathrm{I}} (\mathrm{G}_\iota \circ \mathrm{H}) \quad \text{and} \quad \mathrm{H} \circ \left( \bigcup_{\iota \in \mathrm{I}} \mathrm{G}_\iota \right) = \bigcup_{\iota \in \mathrm{I}} (\mathrm{H} \circ \mathrm{G}_\iota).
Solution

No solution has been written yet.

Cited by

Nothing.

Cites

Nothing.

Transcribed from the printed volume. Not translated.