Bourbaki

Proposition 3

Tag 03JH, permanent. Cite it as [Bourbaki, Tag 03JH].

Theory of Sets, chapter III, § 1. Order relations. Ordered sets

Let E be an ordered set and let E′' be the disjoint union of E and a set {a}\{a\} consisting of a single element. Then there exists a unique ordering on E′' which induces the given ordering on E and for which aa is the greatest element of E′'.

For if G is the graph of the ordering on E, the graph of an ordering on E′' which satisfies the conditions of the Proposition must be the union G′' of G and the set of all pairs (x,a)(x, a) where x∈E′x \in E'; conversely, it is clear that G′' is the graph of an ordering on E′' which satisfies the given conditions.

¶ The ordered set E′' is said to be obtained by adjoining a greatest element aa to E (cf. Exercise 3).

¶ A subset AA of a preordered set EE is said to be cofinal (resp. coinitial) in EE if for every x∈Ex\in E there exists y∈Ay\in A such that x≤yx\leq y (resp. y≤xy\leq x). To say that an ordered set EE has a greatest (resp. least) element therefore means that EE has a cofinal (resp. coinitial) subset consisting of a single element.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2004, Springer. Not translated.