Let(xλμ)(λ,μ)∈L×Mbe a "double" family of elements of an ordered setEsuch that for eachμ∈Mthe family(xλμ)λ∈Lhas a least upper bound inE. For the family(xλμ)(λ,μ)∈L×Mto have a least upper bound inE, it is necessary and sufficient that the family(λ∈Lsupxλμ)μ∈Mshould have a leastupper bound in E, and then we have
(2)(λ,μ)∈L×Msupxλμ=μ∈Msup(λ∈Lsupxλμ).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.