Bourbaki

Example 1

Tag 03SS, permanent. Cite it as [Bourbaki, Tag 03SS].

Theory of Sets, chapter III, § 1. Order relations. Ordered sets

\* In the ordered set E=RE = \mathbf{R} of real numbers, consider the subset F=QF = \mathbf{Q} of rational numbers and the set A⊂FA \subset F of rational numbers <2< \sqrt{2}; sup⁡EA\sup_E A exists but sup⁡FA\sup_F A does not.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

Nothing.

Transcribed from the printed edition, 2004, Springer. Not translated.