Bourbaki

Proposition 7

Tag 04BV, permanent. Cite it as [Bourbaki, Tag 04BV].

Commutative Algebra, chapter II, § 5. Finitely generated projective modules. Invertible fractional ideals

The set P(A)P(A) of classes of projective A-modules of rank 1, with the law of composition (6), is a commutative group. If M is a projective A-module of rank 1 and M∗M^* is its dual, then

(7)

cl(M∗)=−cl(M)andcl(A)=0. \mathrm{cl}(M^*) = -\mathrm{cl}(M) \quad \text{and} \quad \mathrm{cl}(A) = 0.

The associativity and commutativity of the tensor product show that the law of composition (6) is associative and commutative; the isomorphism between A⊗AMA \otimes_A M and M prove that cl(A)\mathrm{cl}(A) is the identity element under this law and, by virtue of Theorem 3, cl(M)+cl(M∗)=cl(A)\mathrm{cl}(M) + \mathrm{cl}(M^*) = \mathrm{cl}(A), whence the proposition.

Let B be a commutative A-algebra and M a projective A-module of rank 1; then M(B)=B⊗AMM_{(B)} = B \otimes_A M is a projective B-module of rank 1 (no. 3, Proposition 4). Then there exists a mapping called canonical ϕ:P(A)→P(B)\phi : P(A) \to P(B) such that

(8)

ϕ(cl(M))=cl(M(B)). \phi(\mathrm{cl}(M)) = \mathrm{cl}(M_{(B)}).

The equation M(B)⊗BN(B)=(M⊗AN)(B)M_{(B)} \otimes_B N_{(B)} = (M \otimes_A N)_{(B)} for two A-modules M, N proves that the mapping ϕ\phi is a commutative group homomorphism.

Remark (2). Condition (e) of Theorem 1 (equivalent to the fact that P is projective and finitely generated) may also be expressed by saying that the sheaf of modules P~\tilde{P} over X=Spec(A)X = \mathrm{Spec}(A) associated() with P is locally free and of finite type* and may therefore be interpreted as the sheaf of sections of a vector bundle over X. Conversely, every vector bundle over X arises from a finitely generated projective module, which is determined to within a unique isomorphism; the projective modules of rank nn thus correspond to the vector bundles all of whose fibres have dimension nn. In particular, the vector bundles of rank 1 correspond to the projective modules of rank 1. If we denote by OX\mathscr{O}_X the structure sheaf A~\tilde{A} and by OX∗\mathscr{O}_X^* the sheaf of units of OX\mathscr{O}_X (whose sections over an open set U of X are the invertible elements of the ring of sections of OX\mathscr{O}_X over U), it follows that the group P(A)P(A) is isomorphic to the first cohomology group H1(X,OX∗)H^1(X, \mathscr{O}_X^*).*

(* See A. Grothendieck, Éléments de géométrie algébrique, I (§ 1) (Publ. Math. I.H.E.S., no. 4, 1960).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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