Bourbaki

Exercise 1, § 6

Algebra, X, p. 189

Let ρ:A→B\rho : A \to B be a ring homomorphism, M,NM, N two left BB-modules, PP a right BB-module. a) Let LBL_B (resp. LAL_A) be a projective resolution of the BB-module (resp. of the AA-module) MM. Prove that there exists an AA-linear morphism of resolutions LA→LBL_A \to L_B, unique up to homotopy; deduce graded kk-homomorphisms of degree zero

α:Tor⁡A(P,M)→Tor⁡B(P,M)β:Ext⁡B(M,N)→Ext⁡A(M,N). \alpha : \operatorname{Tor}^A(P, M) \to \operatorname{Tor}^B(P, M) \qquad \beta : \operatorname{Ext}_B(M, N) \to \operatorname{Ext}_A(M, N) .
b) Consider the canonical homomorphisms (X, p. 109)
λ:Tor⁡A(P,M)→Tor⁡B(P⊗AB,M)μ:Tor⁡A(P,M)→Tor⁡B(P,B⊗AM) \lambda : \operatorname{Tor}^A(P, M) \to \operatorname{Tor}^B(P \otimes_A B, M) \qquad \mu : \operatorname{Tor}^A(P, M) \to \operatorname{Tor}^B(P, B \otimes_A M)
ν:Ext⁡B(B⊗AM,N)→Ext⁡A(M,N)ρ:Ext⁡B(M,Hom⁡A(B,N))→Ext⁡A(M,N). \nu : \operatorname{Ext}_B(B \otimes_A M, N) \to \operatorname{Ext}_A(M, N) \qquad \rho : \operatorname{Ext}_B(M, \operatorname{Hom}_A(B, N)) \to \operatorname{Ext}_A(M, N) .
Let m:B⊗AM→M,p:P⊗AB→Bm : B \otimes_A M \to M, p : P \otimes_A B \to B and n:N→Hom⁡A(B,N)n : N \to \operatorname{Hom}_A(B, N) be the BB-homomorphisms defined by m(b⊗x)=bx,p(y⊗b)=ybm(b \otimes x) = bx, p(y \otimes b) = yb and n(z)(b)=bzn(z)(b) = bz for b∈B,x∈M,y∈P,z∈Nb \in B, x \in M, y \in P, z \in N. Prove the equalities
α=Tor⁡(1P,m)∘μ=Tor⁡(p,1M)∘λ \alpha = \operatorname{Tor}(1_P, m) \circ \mu = \operatorname{Tor}(p, 1_M) \circ \lambda
β=ν∘Ext⁡(m,1N)=ρ∘Ext⁡(1M,n). \beta = \nu \circ \operatorname{Ext}(m, 1_N) = \rho \circ \operatorname{Ext}(1_M, n) .

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.