Bourbaki

Exercise 35, § 1

Topological Vector Spaces, V, p. 67

It is set in small type as supplementary.

We denote by E a finite-dimensional real Hilbert space of dimension nn, by S the unit sphere of E and by mm the unique positive measure of norm 1 on S invariant under the automorphism group of E. We consider S as a metric space in which the distance is defined by d(x,y)=Arc⁡cos⁡⟨x∣y⟩d(x, y) = \operatorname{Arc}\cos \langle x|y \rangle. For x∈Sx \in S and every real number r⩾0r \geqslant 0, we denote by B(x,r)B(x, r) the set of points yy of SS such that d(x,y)⩽rd(x, y) \leqslant r; for every subset AA of SS and every real number r⩾0r \geqslant 0, we denote by ArA_r the set of points xx of SS such that d(x,A)⩽rd(x, A) \leqslant r.

a) Given two closed subsets AA and BB of SS, we denote by δ(A,B)\delta(A, B) the greatest lower bound of the set of real numbers r⩾0r \geqslant 0 such that A⊂BrA \subset B_r and B⊂ArB \subset A_r. Prove that δ\delta is a distance on the set F\mathscr{F} of closed subsets of SS, and that F\mathscr{F} is a compact metric space for this distance. Prove that the mapping A↦m(A)A \mapsto m(A) of F\mathscr{F} into R\mathbf{R} is upper semi-continuous.

b) Let x0x_0 be a point of SS, HH the hyperplane of EE orthogonal to x0x_0, x1x_1 a point of HH and γ\gamma the circular arc joining x0x_0 to −x0-x_0 by passing through x1x_1, that is to say the set of points of SS of the form x0sin⁡θ+x1cos⁡θx_0 \sin \theta + x_1 \cos \theta with ∣θ∣⩽π/2|\theta| \leqslant \pi/2. For every y∈γy \in \gamma, we put Hy=H+yH_y = H + y and Sy=S∩HyS_y = S \cap H_y; we denote by mym_y the unique positive measure of norm 1 on SyS_y invariant under the automorphism group of EE which leaves x0x_0 fixed.

Let AA be a closed subset of SS and let γ′\gamma' be the set of points yy of γ\gamma such that A∩SyA \cap S_y is nonempty. For every y∈γ′y \in \gamma', there exists a unique real number r(y)r(y) such that 0⩽r(y)⩽π0 \leqslant r(y) \leqslant \pi and that my(A∩Sy)=my(B(y,r(y))∩Sy)m_y(A \cap S_y) = m_y(B(y, r(y)) \cap S_y); we denote by sγ′(A)s_{\gamma'}(A) the union of the sets B(y,r(y))∩SyB(y, r(y)) \cap S_y for yy ranging over γ′\gamma'. Now prove that sγ′(A)s_{\gamma'}(A) is closed and that one has m(A)=m((sγ′(A)))m(A) = m((s_{\gamma'}(A))).

c) For every closed subset AA of SS, one calls the radius of AA the greatest lower bound r(A)r(A) of the set of real numbers r⩾0r \geqslant 0 for which there exists x∈Sx \in S with A⊂B(x,r)A \subset B(x, r). We denote by M(A)M(A) the set of closed subsets CC of SS such that m(C)=m(A)m(C) = m(A) and m(Cε)⩽m(Aε)m(C_\varepsilon) \leqslant m(A_\varepsilon) for every ε>0\varepsilon > 0. Now prove that the following conditions are equivalent for every pair (A,B)(A, B) of closed subsets of SS:

(i) one has m(A)=m(B)m(A) = m(B) and BB is of the form B(x,r)B(x, r) with x∈Sx \in S and r⩾0r \geqslant 0; (ii) one has B∈M(A)B \in M(A) and r(B)⩽r(C)r(B) \leqslant r(C) for every subset CC of AA belonging to M(A)M(A). (Reasoning by induction on nn, one will deduce from b) that sγ′(A)s_{\gamma'}(A) belongs to M(A)M(A) for every closed subset AA of SS; if r>0r > 0 is such that A⊂B(x1,r)A \subset B(x_1, r), show that every point of the boundary of B(x1,r)B(x_1, r) in SS which belongs to sγ′(A)s_{\gamma'}(A) also belongs to AA.)

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.