Exercise 17, § 3
Integration, VIII
The notation and conventions are those of Exercise 15.
a) Let be a bounded measure on ; for the endomorphism of to be surjective (), it is necessary and sufficient that there exist such that for all (where ) (cf. Esp. vect. top., chap. IV, § 5, exerc. 11).
b) If is a base measure , if is not discrete, now prove that is never surjective for (for , use a)), by reducing to the case where the density of with respect to belongs to ; for , reason directly by observing that for and , is uniformly continuous for the right uniform structure).
c) If is commutative, and if the endomorphism of is surjective, now prove that it is bijective (using regularization, prove that if is not injective, the endomorphism of is not injective: one will use chap. IV, § 6, No. 5, cor. of prop. 4).
d) Let and ; now prove that is injective in the such that , but not in , and is not surjective for any value of .
Solution
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