Bourbaki

Exercise 21, § 3

Integration, VIII

Bourbaki marks this one as harder than the rest.

Let GG be a locally compact group, β\beta a left Haar measure on GG; one canonically identifies L1(G,β)L^1(G, \beta) with a subspace of M1(G)\mathscr{M}^1(G).

a) With the notations of § 3, exerc. 11, let A be a relatively compact subset of MIII\mathscr{M}_{\text{III}}, B a subset of L1(G,β)L^1(G, \beta), relatively compact in MIV\mathscr{M}_{\text{IV}}. Now prove that the restriction to A×BA \times B of the mapping (μ,v)→μ∗v(\mu, v) \to \mu * v from MIII×MIV\mathscr{M}_{\text{III}} \times \mathscr{M}_{\text{IV}} into MIV\mathscr{M}_{\text{IV}} is continuous. (Proving first that if A and B are compact, the image of A×BA \times B by this mapping is compact; use exerc. 10 of § 3, as well as the α\alpha criterion) of Chap. V, § 5, exerc. 17. To show afterwards that (μ,v)→μ∗v(\mu, v) \to \mu * v is continuous, use exerc. 11 c) of § 3.)

b) Let Us∞(G)\mathscr{U}_s^\infty(G) be the set of bounded numerical functions and uniformly continuous in G for the left uniform structure. Let TII\mathscr{T}_{\text{II}} denote the topology σ(M1(G),Us∞(G))\sigma(\mathscr{M}^1(G), \mathscr{U}_s^\infty(G)), and MII\mathscr{M}_{\text{II}} the space M1(G)\mathscr{M}^1(G) endowed with TII\mathscr{T}_{\text{II}}. Taking G=RG = \mathbf{R}, give an example of a sequence (μn)(\mu_n) of measures on G tending to 0 for TII\mathscr{T}_{\text{II}} and of a sequence (fn)(f_n) of functions of L1(G,β)L^1(G, \beta), tending to 0 for TIV\mathscr{T}_{\text{IV}} (or, equivalently, for the topology σ(L1(G,β),L∞(G,β))\sigma(L^1(G, \beta), L^\infty(G, \beta))), such that the sequence (μn∗fn)(\mu_n * f_n) does not tend to 0 for TIV\mathscr{T}_{\text{IV}} (take fn(t)=sin⁡ntf_n(t) = \sin nt in the interval [0,π][0, \pi], fn(t)=0f_n(t) = 0 elsewhere).

c) Let A be a relatively compact subset of MII\mathscr{M}_{\text{II}}, B a subset of L1(G,β)L^1(G, \beta), relatively compact for the topology of the norm ∥f∥1\|f\|_1. Now prove that the restriction to A×BA \times B of the mapping (μ,f)→μ∗f(\mu, f) \to \mu * f from MIII×L1(G,β)\mathscr{M}_{\text{III}} \times L^1(G, \beta) into L1(G,β)L^1(G, \beta) is continuous (L1(G,β)L^1(G, \beta) being endowed with its normed space topology). (Reduce to proving that for f∈K(G)f \in \mathscr{K}(G), the mapping μ→μ∗f\mu \to \mu * f from MII\mathscr{M}_{\text{II}} into L1(G,β)L^1(G, \beta) is continuous in A. Using the fact that for g∈L∞(G,β)g \in L^\infty(G, \beta) and f∈K(G)f \in \mathscr{K}(G), g∗fg * f is uniformly continuous for the left uniform structure, first show that the mapping μ→μ∗f\mu \to \mu * f from MII\mathscr{M}_{\text{II}} into MIV\mathscr{M}_{\text{IV}} is continuous. Using then exerc. 20 a), reduce to proving that if C is a subset of L1(G,β)L^1(G, \beta) compact for the topology σ(L1(G,β),L∞(G,β))\sigma(L^1(G, \beta), L^\infty(G, \beta)) and h∈K(G)h \in \mathscr{K}(G), the mapping μ→μ∗h\mu \to \mu * h from C into L1(G,β)L^1(G, \beta) is continuous when L1(G,β)L^1(G, \beta) is endowed with its normed space topology. By the same reasoning as in a), show that it suffices for this to prove that the image of C by this mapping is compact for the normed space topology. Use for this the th. of Šmulian, the fact that C is tight (§ 3, exerc. 10) and the th. of Lebesgue).

d) Let A be a relatively compact subset of MII\mathscr{M}_{II} containing 0, B a relatively compact subset of MI\mathscr{M}_I; now prove that for every v0∈Bv_0 \in B the restriction to A×BA \times B of the mapping (μ,ν)→μ∗ν(\mu, \nu) \to \mu * \nu from MII×MI\mathscr{M}_{II} \times \mathscr{M}_I into MII\mathscr{M}_{II} is continuous at the point (0,v0)(0, v_0). (Use exerc. 20 a), and exerc. 8 c.)

e) Let A be a bounded subset of M1(G)\mathscr{M}^1(G), ff a function of L1(G,β)L^1(G, \beta); now prove that the restriction to A of the mapping μ→μ∗f\mu \to \mu * f from MIII\mathscr{M}_{III} into MIV\mathscr{M}_{IV} is continuous.

f) Let M+1(G)\mathscr{M}_+^1(G) be the set of bounded positive measures on G. Prove that if a subset A of M+1(G)\mathscr{M}_+^1(G) is compact for TII\mathscr{T}_{II} it is also compact for TIII\mathscr{T}_{III}. (Reduce to proving that A is a tight set. Argue by contradiction, using the fact that for f∈K(G)f \in \mathscr{K}(G), the image of A by the mapping μ→μ∗f\mu \to \mu * f is a tight set by virtue of c.).

g) Prove that for G=RG = \mathbf{R}, the topologies induced on M+1(G)\mathscr{M}_+^1(G) by TII\mathscr{T}_{II} and TIII\mathscr{T}_{III} are distinct.

Solution

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Machine translation of the English, by gpt-5-6-mini, gpt-5-6. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.