Bourbaki

Exercise 11, § 8

Algebra, III, 640

Let Δ\Delta be the determinant of a square matrix XX of order nn and Δp\Delta_p the determinant of the square matrix ∧^pX\hat{\wedge}^p X, of order (np)\binom{n}{p}. Show that

ΔpΔn−p=Δ(p)(n) \Delta_p \Delta_{n-p} = \Delta^{(n)}_{(p)}

(use formulae (21) and (22) of no. 6).

Solution

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Transcribed from the printed volume. Not translated.