Exercise 4, § 8 Algebra, III, 638 Calculate the determinant Δn=∣a1+b1b1b1⋯b1b2a2+b2b2⋯b2⋯⋯⋯⋯⋯bnbnbn⋯an+bn∣ \Delta_n = \begin{vmatrix} a_1 + b_1 & b_1 & b_1 & \cdots & b_1 \\ b_2 & a_2 + b_2 & b_2 & \cdots & b_2 \\ \cdots & \cdots & \cdots & \cdots & \cdots \\ b_n & b_n & b_n & \cdots & a_n + b_n \end{vmatrix} Δn=a1+b1b2⋯bnb1a2+b2⋯bnb1b2⋯bn⋯⋯⋯⋯b1b2⋯an+bn (express Δn\Delta_nΔn in terms of Δn−1\Delta_{n-1}Δn−1). Solution No solution has been written yet.