Exercise 10, § 6 Algebra, IV, p. 100 Let a∈Aa \in \mathbf{A}a∈A. For each polynomial h∈A[X]h \in \mathbf{A}[X]h∈A[X] put ha(X)=h(X+a)h_a(X) = h(X + a)ha(X)=h(X+a); show that res(fa,ga)=res(f,g)\operatorname{res}(f_a, g_a) = \operatorname{res}(f, g)res(fa,ga)=res(f,g), dis(fa)=dis(f)\operatorname{dis}(f_a) = \operatorname{dis}(f)dis(fa)=dis(f). Solution No solution has been written yet.