Bourbaki

Exercise 10, § 6

Algebra, IV, p. 100

Let a∈Aa \in \mathbf{A}. For each polynomial h∈A[X]h \in \mathbf{A}[X] put ha(X)=h(X+a)h_a(X) = h(X + a); show that res⁡(fa,ga)=res⁡(f,g)\operatorname{res}(f_a, g_a) = \operatorname{res}(f, g), dis⁡(fa)=dis⁡(f)\operatorname{dis}(f_a) = \operatorname{dis}(f).

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Transcribed from the printed volume. Not translated.