Bourbaki

Exercise 12, § 11

Tag 01K5, permanent. Cite it as [Bourbaki, Tag 01K5].

Lie Groups and Lie Algebras, VIII, 263

Bourbaki marks this one as harder than the rest.

Assume that g\mathfrak{g} is semi-simple. Let x∈gx\in \mathfrak{g} and let ss (resp. nn) be the semi-simple (resp. nilpotent) component of xx. Let ax\mathfrak{a}_x (resp. as\mathfrak{a}_s) be the commutant of xx (resp. ss) in g\mathfrak{g}.

a) Show that nn is a nilpotent element of the semi-simple algebra D(as)\mathscr{D}(\mathfrak{a}_s), and that the commutant of nn in as\mathfrak{a}_s is equal to ax\mathfrak{a}_x. Deduce that dimax<\mathfrak{a}_x< dim as\mathfrak{a}_s if n≠0n\not= 0, i.e. if xx is not semi-simple.

b) Show that dimax=\mathfrak{a}_x= rk(g\mathfrak{g}) if and only if nn is a principal nilpotent element of D(as)\mathscr{D}(\mathfrak{a}_s).

c) Put G = Aute(g)_e(\mathfrak{g}). Show that, for all λ∈k\lambda \in k, there exists σλ∈G\sigma_{\lambda}\in G such that σλx=s+λ2n\sigma_{\lambda}x=s+\lambda^2n. (Show that, if n≠0n\not= 0, there exists an sl2\mathfrak{s}\mathfrak{l}_2-triplet in as\mathfrak{a}_s of which the first component is nn, and deduce a homomorphism φ:SL(2,k)→G\varphi :\mathbf{S}\mathbf{L}(2, k)\rightarrow G; take σλ\sigma_{\lambda} to be the image under φ\varphi of a suitable diagonal element of SL(2,k).\mathbf{S}\mathbf{L}(2, k).) Deduce that ss belongs to the closure of G.xG.x in the Zariski topology.

d) Show that, if xx is not semi-simple, xx does not belong to the closure of G.sG.s in the Zariski topology (use the inequality dimax<\mathfrak{a}_x< dim as\mathfrak{a}_s, cf. aa))).

20^{20}For more details on Exercises 6 to 11, see: B. KOSTANT, The principal threedimensional subgroup and the Betti numbers of a complex simple Lie group,

Amer. J. Math., Vol. LXXXI (1959), pp. 973-1032. e) Assume that kk is algebraically closed. Prove the equivalence of the following properties:

(i) xx is semi-simple;

(ii) G.xG.x is closed in g\mathfrak{g} in the Zariski topology.

(The implication (ii) =⇒=\Rightarrow (i) follows from cc). If (i) is satisfied, and if x′x' is in the closure of G.xG.x, Exerc. 15 of §8 shows that the semi-simple component s′s' of x′x' belongs to G.xG.x, so x′x' belongs to the closure of G.s′G.s'; conclude by applying d) to x′x' and s′.)s'.)

f) Assume that kk is algebraically closed. Let FxF_x be the set of elements y∈gy\in \mathfrak{g} such that f(x)=f(y)f(x) =f(y) for every invariant polynomial function ff on g\mathfrak{g}; we have y∈Fxy\in F_x if and only if the semi-simple component of yy is G-conjugate to s(s(§8, Exerc. 17). Show that FxF_x is the union of a finite number of orbits of G, and that this number is ≤3l(x)\leq 3^{l(x)}, where l(x)l(x) is the rank of D(as)\mathscr{D}(\mathfrak{a}_s). Only one of these orbits is closed: that of ss; only one is open in Fx:F_x: that consisting of the elements y∈Fxy\in F_x such that dim ay=\mathfrak{a}_y= rk(g\mathfrak{g}).

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