Bourbaki

Exercise 1, § 3

General Topology, IV, 387

Let xx be a real number ⩾0\geqslant 0 and let pp and qq be two integers >0> 0. Prove the relations

(x1/p)1/q=x1/pq,(xp)1/q=(x1/q)p,x1/px1/q=(xp+q)1/pq. (x^{1/p})^{1/q} = x^{1/pq}, \quad (x^p)^{1/q} = (x^{1/q})^p, \quad x^{1/p} x^{1/q} = (x^{p+q})^{1/pq}.
Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.