Bourbaki

Proposition 7

Tag 009E, permanent. Cite it as [Bourbaki, Tag 009E].

Algebra, VIII, p. 140, § 8. Semisimple Rings

Let A be a semisimple ring.

a) Every finitely generated A-module is reflexive (II, §2, No. 7, p. 239).

b) For every simple left A-module S, the right A-module S∗S^* dual to S is simple, and the mapping λ↦\lambda \mapsto cl(λ∗\lambda^*) defines a bijection from the set of classes of simple A-modules to the set of classes of simple right A-modules.

c) Let M be a finitely generated left A-module. The right A-module M∗M^* dual to M is finitely generated and has the same length as M. Moreover, we have [M:S]=[M∗:S∗][M : S] = [M^*: S^*] for every simple A-module S.

Let M be a finitely generated A-module.

By Proposition 4 of VIII, p. 138, the A-module M is finitely generated and projective; it is therefore reflexive by Corollary 4 of II, §2, No. 7, p. 240. In particular, every simple A-module is reflexive. It also follows that two finitely generated left modules are isomorphic if and only if their duals are.

Let S be a simple left A-module. Let (Ti)i∈I(T_i)_{i\in I} be a family of simple right A-modules with direct sum the dual S∗S^* of S. Since S is reflexive, it is isomorphic to (S∗)∗(S^*)^* and therefore to ∏i∈ITi∗\prod_{i\in I}T^*_i. Each of the modules TiT_i is reflexive; in particular, we have Ti∗≠0T^*_i\not= 0 for every i∈Ii\in I. Since the simple module S is isomorphic to ∏i∈ITi∗\prod_{i\in I}T^*_i, the set I has a single element, so S∗S^* is simple.

Since M is semisimple and finitely generated, it is the direct sum of simple submodules S1,...,SrS_1, . . . ,S_r. Then M∗M^* is isomorphic to the direct sum of the family S1∗,...,Sr∗S^*_1, . . . ,S^*_r, and we have just seen that the modules Si∗S^*_i are simple. Assertion c) follows immediately.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2023, Springer Nature. Not translated.