Bourbaki

Example

Tag 009G, permanent. Cite it as [Bourbaki, Tag 009G].

Algebra, VIII, p. 141, § 8. Semisimple Rings

Let K be an algebraically closed commutative field, and let A be a semisimple algebra of finite degree over K. Let (Vi)i∈I(V_i)_{i\in I} be a family of simple A-modules such that every simple A-module is isomorphic to a unique ViV_i. Then I is a finite set (VIII, p. 136, Proposition 1), the vector spaces ViV_i are finite-dimensional over the field K, the commutant of ViV_i is equal to K⋅1ViK\cdot 1_{V_i} (VIII, p. 47, Theorem 1), and the mapping a↦(aVi)i∈Ia\mapsto (a_{V_i})_{i\in I} is an algebra isomorphism from A to ∏i∈I\prod_{i\in I} EndK(Vi)_K(V_i) (Proposition 8).

We have defined (VIII, p. 50) a minimal two-sided ideal as a minimal element of the set of nonzero two-sided ideals, ordered by inclusion. In other words, a minimal two-sided ideal a\mathfrak{a} of A is a simple (A(A, A)-sub-bimodule of sAd_sA_d. Likewise, we define a maximal two-sided ideal of A as a maximal element of the set of proper two-sided ideals of A. A maximal two-sided ideal a\mathfrak{a} of A is simply a maximal (A(A, A)-sub-bimodule of sAd_sA_d (VIII, p. 48, Definition 2). If the ring A is simple, then the ideal 0 is a maximal two-sided ideal of A and A is a minimal two-sided ideal.

For any λ∈S\lambda \in \mathscr{S}, we denote the isotypical component of type λ\lambda of the A-module AsA_s by aλ\mathfrak{a}_{\lambda}. For any subset Λ of S\mathscr{S}, we set aΛ=∑λ∈Λaλ\mathfrak{a}_{\Lambda}=\sum_{\lambda\in\Lambda}\mathfrak{a}_{\lambda}.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 2023, Springer Nature. Not translated.