Bourbaki

Remark 3

Tag 00R8, permanent. Cite it as [Bourbaki, Tag 00R8].

Algebra, VIII, p. 147, § 8. Semisimple Rings

Applying the previous results to the opposite ring of A, we see, in particular, that a monogenous right A-module M is projective if and only if there exists an idempotent ee in A such that M is isomorphic to eAeA. Moreover, eAeA is an indecomposable right module if and only if ee is indecomposable.

Now suppose that the ring A is semisimple, and denote the set of classes of simple left A-modules by S\mathscr{S}. The A-module AsA_s is semisimple, and every submodule of AsA_s is a direct factor. Let a\mathfrak{a} be a left ideal of A. By the above, there exists an idempotent ee in A such that a=Ae\mathfrak{a}= Ae, and the A-module a\mathfrak{a} is simple if and only if it is indecomposable, that is, if and only if ee is indecomposable.

Let (mi)i∈I(\mathfrak{m}_i)_{i\in I} be a family of minimal left ideals of A such that we have As=⊕i∈ImiA_s=\oplus_{i\in I}\mathfrak{m}_i. By Proposition 14, there exists a partition (εi)i∈I(\varepsilon_i)_{i\in I} of 1 consisting of indecomposable idempotents such that mi=Aεi\mathfrak{m}_i= A\varepsilon_i for every i∈Ii\in I.

For every λ∈S\lambda \in \mathscr{S}, let SλS_{\lambda} be an A-module of class λ\lambda, and let aλ\mathfrak{a}_{\lambda} be the isotypical component of type λ\lambda of the A-module AsA_s. Since A is the direct sum of the family (aλ)λ∈S(\mathfrak{a}_{\lambda})_{\lambda\in\mathscr{S}}, there exists a partition (eλ)λ∈S(e_{\lambda})_{\lambda\in\mathscr{S}} of 1 such that aλ=Aeλ\mathfrak{a}_{\lambda}= Ae_{\lambda} for every λ∈S\lambda \in \mathscr{S}. For λ∈S\lambda \in \mathscr{S}, denote by I(λ)I(\lambda ) the set of indices i∈Ii\in I such that the simple A-module mi\mathfrak{m}_i is of type λ\lambda. By Proposition 4, b) of VIII, p. 65, we have

aλ=⨁i∈I(λ)mi(3) \mathfrak{a}_{\lambda}=\bigoplus_{i\in I(\lambda)}\mathfrak{m}_i \tag{3}

The idempotent eλe_{\lambda} is the component of 1 in aλ\mathfrak{a}_{\lambda}, so eλ=∑i∈I(λ)εie_{\lambda}=\sum_{i\in I(\lambda)}\varepsilon_i.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed edition, 2023, Springer Nature. Not translated.