Let V and V′ be finite dimensional vector spaces, and let r:S→ End(V) and r′:S→ End(V′) be maps satisfying condition (AC). Let f:V→V′ be a surjective linear map such that f(r(s)v)=r′(s)f(v) for s∈S and v∈V. Then f(Vλ(S))=V′λ(S) for all λ∈P.
In view of Prop. 1, we are reduced to the case in which k is algebraically closed. We have V=⨁λ∈PVλ(S), V′=⨁λ∈PV′λ(S) by Th. 1, and V′=f(V)=∑λ∈Pf(Vλ(S)). Finally, f(Vλ(S))⊂V′λ(S) by Prop. 2 (i), hence the corollary.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.