Bourbaki

Corollary 3

Tag 00SR, permanent. Cite it as [Bourbaki, Tag 00SR].

Lie Groups and Lie Algebras, chapter VII, § 1. Primary decomposition of linear representations

Let V and V′V' be finite dimensional vector spaces, and let r:S→r: S\rightarrow End(V) and r′:S→r': S\rightarrow End(V′') be maps satisfying condition (AC). Let f:V→V′f: V\rightarrow V' be a surjective linear map such that f(r(s)v)=r′(s)f(v)f(r(s)v) =r'(s)f(v) for s∈Ss\in S and v∈Vv\in V. Then f(Vλ(S))=V′λ(S)f(V^{\lambda}{(S)) = V'}^{\lambda}(S) for all λ∈P\lambda \in P.

In view of Prop. 1, we are reduced to the case in which kk is algebraically closed. We have V=⨁λ∈PVλV =\bigoplus_{\lambda\in P}V^{\lambda}(S), V′=⨁λ∈PV′λ(S)V'=\bigoplus_{\lambda\in P}{V'}^{\lambda}(S) by Th. 1, and V′=f(V)=V'=f(V) = ∑λ∈Pf(Vλ(S))\sum_{\lambda\in P}f(V^{\lambda}(S)). Finally, f(Vλ(S))⊂V′λ(S)f(V^{\lambda}(S))\subset {V'}^{\lambda}(S) by Prop. 2 (i), hence the corollary.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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