Let (Xj)j∈J and (Yj)j∈J be families of topological spaces having the same index set. For each j∈J, let fj and gj be continuous mappings of Xj into Yj. If, for each j∈J, the mappings fj and gj are homotopic, the same is true of the product mappings f:(xj)↦(fj(xj)) and g:(xj)↦(gj(xj)) of ∏j∈JXj into ∏j∈JYj.
Suppose that we have [fj]=[gj] for each j∈J. We have [prj]∘[f]=[fj∘ prj] and [prj]∘[g]=[gj∘ prj], hence [prj]∘[f]= [prj]∘[g] by prop. 2, whence [f]=[g] by prop. 3.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.