Bourbaki

Example 2

Tag 01VC, permanent. Cite it as [Bourbaki, Tag 01VC].

Topologie algébrique, chapter III, § 1. Homotopies, homéotopies

Let X be a nonempty topological space. In order that X be homotopy equivalent to a space reduced to one point, it is necessary and sufficient that there exist a constant mapping p:X→p: X\rightarrow X which is homotopic to the identity mapping of X. (This is then so for every constant mapping q:X→Xq: X\rightarrow X, since [p]=[p]∘[q]=[p] = [p]\circ [q] = [IdX]∘[q]=[q]_X]\circ [q] = [q].) Indeed, let P be a space reduced to one point, f:P→Xf: P\rightarrow X a mapping and g:X→Pg: X\rightarrow P the unique mapping of X into P. We have g∘f=g\circ f= IdP_P; in order that ff be a homotopy equivalence, it is necessary and sufficient that f∘gf\circ g be homotopic to IdX_X. Now, f∘gf\circ g is constant, of image f(P)f(P).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, gpt-5-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.