Let X′,Y′ be topological spaces and let f′:X′→Y′ be a continuous mapping. Let u:X→X′ and v:Y→Y′ be continuous mappings such that f′∘u=v∘f. There exists a unique continuous mapping w: Cyl(f)→ Cyl(f′) such that w∘αf=αf′∘(u× IdI) and w∘βf=βf′∘v.
According to prop. 4, applied to Z = Y and β= IdY, there exists a unique continuous mapping γf: Cyl(f)→Y such that γf(αf(x,s))=f(x) and γf(βf(y))=y for x∈X,s∈I and y∈Y.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.