Bourbaki

Example 1

Tag 01VO, permanent. Cite it as [Bourbaki, Tag 01VO].

Topologie algébrique, chapter III, § 1. Homotopies, homéotopies

Let X′,Y′X',Y' be topological spaces and let f′:X′→Y′f': X'\rightarrow Y' be a continuous mapping. Let u:X→X′u: X\rightarrow X' and v:Y→Y′v: Y\rightarrow Y' be continuous mappings such that f′∘u=v∘ff'\circ u=v\circ f. There exists a unique continuous mapping w:w: Cyl(ff)→\rightarrow Cyl(f′f') such that w∘αf=αf′∘(u×w\circ \alpha_f=\alpha_{f'}\circ (u\times IdI)_{\mathbf{I}}) and w∘βf=βf′∘vw\circ \beta_f=\beta_{f'}\circ v.

According to prop. 4, applied to Z = Y and β=\beta = IdY_Y, there exists a unique continuous mapping γf:\gamma_f: Cyl(ff)→Y\rightarrow Y such that γf(αf(x,s))=f(x)\gamma_f(\alpha_f(x, s)) =f(x) and γf(βf(y))=y\gamma_f(\beta_f(y)) =y for x∈X,s∈Ix\in X,s\in \mathbf{I} and y∈Yy\in Y.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

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Cites

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, gpt-5-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.