Let B′ be a topological space, let A′ be a subspace of B′, and let f′:A′→ X be a continuous mapping. Let v:B→B′ be a continuous mapping such that v(A)⊂A′ and f = f′∘(v∣A). Let w:X∪fB→X∪f′B′ be the unique continuous mapping such that w∘αf=αf′ and w∘βf=βf′∘v. If v defines a homotopy equivalence of the pair (B,A) onto the pair (B′,A′), then w defines a homotopy equivalence of the pair (X∪fB,αf(X)) onto the pair (X∪f′B′,αf′(X)).
Let v′:B′→B be a continuous mapping, let τ:B×I→B be a homotopy fixed on A joining IdB to v′∘v, and let τ′:B′×I→B′ be a homotopy fixed on A′ joining IdB′ to v∘v′. For a′∈A′ and a=v′(a′), we have the relations a′=v(a) and βf(v′(a′))=βf(a)=αf(f(a))=αf(f′(a′)). By Prop. 8, a), there exists a unique mapping w′:X∪f′B′→ X∪fB such that w′∘αf′=αf′ and w′∘βf′=βf∘v′. By Prop. 8, b), there exists a unique homotopy η:(X∪fB)×I→X∪f′B′ such that η(αf(x),t)=αf′(x) and η(βf(b),t)=βf′(τ(b,t)) for x∈X,b∈B and t∈I. Analogously there exists a unique homotopy η′:(X∪f′B′)×I→ X∪fB such that η′(αf′(x),t)=αf(x) and η′(βf′(b),t)=βf(τ′(b,t)) for x∈X,b∈B′ and t∈I. The mapping from (X∪fB)×I into X∪fB given by (x,t)↦η′(η(x,t),t) is then a homotopy fixed on αf(X) joining the identity mapping of X∪fB to the mapping w′∘w. Analogously, the mapping from (X∪f′B′)×I into X∪f′B′ given by (x,t)↦η(η′(x,t),t) is a homotopy fixed on αf′(X) joining the identity mapping of X∪f′B′ to the mapping w∘w′. The corollary follows.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
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