Bourbaki

Lemma 5

Tag 021K, permanent. Cite it as [Bourbaki, Tag 021K].

Topologie algébrique, chapter IV, § 2. Groupes de Poincaré des espaces délaçables

The set Γ is a meagre subset of K×KK\times K.

Let Z denote the space K×K×Cc(I×I;X)K\times K\times \mathscr{C}_c(\mathbf{I}\times \mathbf{I}; X). The topology of the space Cc(I×I;X)\mathscr{C}_c(\mathbf{I}\times \mathbf{I}; X) is defined by the distance δ\delta given by δ(h,h′)=\delta (h, h') = supu∈I×Id(h(u),h′(u))_{u\in\mathbf{I}\times\mathbf{I}}d(h(u), h'(u)) and it is complete for this distance (TG, X, p. 20, corollaire and TG, X, p. 9, cor. 1); after TG, X, p. 24, th. 1, this topology is of countable type. The space Cc(I×I;X)\mathscr{C}_c(\mathbf{I}\times \mathbf{I}; X) is therefore a Polish space. The same is true of the space Z, for K is a Polish space (TG, IX, p. 57, prop. 1).

Let H be the subset of Z consisting of the triples (ε,ε′,h)(\varepsilon , \varepsilon ', h) such that hh is a strict homotopy joining cεc_{\varepsilon} to cε′c_{\varepsilon'}. The mappings from Z into X2X^2 given by at:(ε,ε′,h)↦(cε(t),h(t,0)),bt:(ε,ε′,h)↦a_t: (\varepsilon , \varepsilon ', h)\mapsto (c_{\varepsilon}(t), h(t,0)),b_t: (\varepsilon , \varepsilon ', h)\mapsto (cε′(t),h(t,1))(c_{\varepsilon'}(t), h(t,1)) and ct:(ε,ε′,h)↦(h(0,t),h(1,t))c_t: (\varepsilon , \varepsilon ', h)\mapsto (h(0, t), h(1, t)) are continuous, for every t∈It\in \mathbf{I}, because the mapping ε↦cε\varepsilon \mapsto c_{\varepsilon} from K into Ωa(X)\Omega_a(X) is continuous, and analogously the mappings h↦h(s,t)h\mapsto h(s, t) from Cc(I×I;X)\mathscr{C}_c(\mathbf{I}\times \mathbf{I}; X) into X.

By definition, H is the intersection of the sets at−1(ΔX),bt−1(ΔX)\overset{-1}{a_{t}}(\Delta_X),\overset{-1}{b_{t}}(\Delta_X) and ct−1((a,a))\overset{-1}{c_{t}}((a, a)), for t∈It\in \mathbf{I}, where ΔX\Delta_X denotes the diagonal of X. This proves that H is a closed subset of Z.

It follows that H is a Polish space. Let p:Z→K×Kp: Z\rightarrow K\times K be the canonical projection; we have Γ=p(H)\Gamma =p(H) by definition. Since K×KK\times K is separated, Γ is a Souslin subset of K×KK\times K (TG, IX, p. 59, déf. 2). After IV, p. 362, prop. 7, it is an approachable subset of K×KK\times K.

Suppose that Γ is not meagre. The space K×KK\times K is a compact topological space and therefore a Baire space (TG, IX, p. 55, th. 1). Endow the group G0G_0 of permutations of the set {0,1}\{0,1\} with the discrete topology; let the product topological group G=G0NG = G^{\mathbf{N}}_0 operate diagonally in K={0,1}NK =\{0,1\}^{\mathbf{N}}. The group G then operates continuously in K×KK\times K by the mapping (g,(x,y))↦(x,g⋅y)(g,(x, y))\mapsto (x, g\cdot y). After Lemma 4, the set V of elements g∈Gg\in G such that Γ∩g⋅Γ=∅̸\Gamma \cap g\cdot \Gamma =\not\emptyset is a neighbourhood of the identity element of G.

Let g∈Vg\in V; let (ε,ε′)∈Γ∩gΓ(\varepsilon , \varepsilon ')\in \Gamma \cap g\Gamma. Since (ε,ε′)∈Γ(\varepsilon , \varepsilon ')\in \Gamma, we have R{ε,ε′}R\{\varepsilon , \varepsilon '\}; since (ε,ε′)∈gΓ,g−1⋅(ε,ε′)=(ε,g−1ε′)∈Γ(\varepsilon , \varepsilon ')\in g\Gamma ,g^{-1}\cdot (\varepsilon , \varepsilon ') = (\varepsilon , g^{-1}\varepsilon ')\in \Gamma, so that R{ε,g−1ε′}R\{\varepsilon , g^{-1}\varepsilon '\}. We have thus proved that, for every g∈Vg\in V, there exists ε∈K\varepsilon \in K such that ε\varepsilon and gεg\varepsilon are equivalent for R.

For m∈Nm\in \mathbf{N}, let τm\tau_m denote the element of G all of whose terms are equal to ee except that with index mm, which is equal to the nontrivial element τ\tau of G0G_0. There exists an integer mm such that τm\tau_m belongs to V; let then ε∈K\varepsilon \in K be such that ε\varepsilon and ε′=τm⋅ε\varepsilon '=\tau_m\cdot \varepsilon are equivalent for R. This implies that the loops cεc_{\varepsilon} and cε′c_{\varepsilon'} are strictly homotopic. By construction, these loops coincide on the intervals [0,2−m−1][0,2^{-m-1}] and [2−m,1][2^{-m},1]; on the interval [2−m−1,2−m][2^{-m-1},2^{-m}], one is the constant mapping with image aa and the other is the mapping t↦cm(2m+1t−1)t\mapsto c_m(2^{m+1}t-1). It follows that cmc_m is strictly homotopic to the constant loop with image {a}\{a\}, hence a contradiction. Lemma 5 is thus proved.

Let us now complete the proof of theorem 2. By Prop. 8, there exists a continuous injective mapping γ\gamma of {0,1}N\{0,1\}^{\mathbf{N}} into K whose image meets each equivalence class for R in at most one point. If kk and k′k' are distinct elements of {0,1}N\{0,1\}^{\mathbf{N}}, the loops cγ(k)c_{\gamma(k)} and cγ(k′)c_{\gamma(k')} are not strictly homotopic in X, and the mapping {0,1}N→π1(X,a)\{0,1\}^{\mathbf{N}}\rightarrow \pi_1(X, a) given by k↦[cγ(k)]k\mapsto [c_{\gamma(k)}] is injective. In particular, Card(π1(X,a)\pi_1(X, a))⩾\geqslant Card({0,1}N\{0,1\}^{\mathbf{N}}) == Card(P(N)\mathfrak{P}(\mathbf{N})). Since X is a metrizable topological space of countable type, the same is true of Ωa(X)\Omega_a(X) (TG, X, p. 24, th. 1). Hence Ωa(X)\Omega_a(X) is homeomorphic to a subspace of [0,1]N[0,1]^{\mathbf{N}} (TG, IX, p. 18, prop. 12) and

Card(Ωa(X)_a(X))⩽\leqslant Card([0,1]N,1]^{\mathbf{N}}) == Card(P(N)N\mathfrak{P}(\mathbf{N})^{\mathbf{N}})

= Card(P(N×N)\mathfrak{P}(\mathbf{N}\times \mathbf{N})) == Card(P(N)\mathfrak{P}(\mathbf{N})).

A fortiori, Card(π1(X,a)\pi_1(X, a))⩽\leqslant Card(P(N)\mathfrak{P}(\mathbf{N})). It then follows from Cor. 2 of E, III, p. 25, that π1(X,a)\pi_1(X, a) has the power of the continuum, which was to be proved.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.