Bourbaki

Lemma 3

Tag 025D, permanent. Cite it as [Bourbaki, Tag 025D].

Théories spectrales, chapter I, § 1. Spectres et caractères

The mapping χ↦\chi \mapsto Ker(χ\chi ) is a bijection of X(A)\mathsf{X}(A) onto the set of regular ideals of codimension 1 of A.

Let us recall (A, VIII, p. 426, Definition 1) that an ideal I of A is said to be regular if the quotient algebra A/IA/I admits a unit element.

Let us prove the lemma. On the one hand, X(A)\mathsf{X}(A) is identified with the set of characters of A~\widetilde{A} which are not zero on A. On the other hand, by A, VIII, p. 428, Prop. 4, the mapping I↦A∩II\mapsto A\cap I is a bijection of the set of maximal ideals of A~\widetilde{A} distinct from A onto the set of regular maximal ideals of A. The lemma then follows from the results of No. 6.

Now suppose that K is a topological field. We then endow X′(A)\mathsf{X}'(A) with the topology of simple convergence on A; the notation X′(A)\mathsf{X}'(A) will henceforth denote the topological space thus obtained. When K=RK =\mathbf{R} or C\mathbf{C}, we shall also call it the weak topology. For every x∈Ax\in A, the function GA′(x)\mathscr{G}'_A(x) on X′(A)\mathsf{X}'(A) is continuous.

If hh is a morphism from A into B, the mapping X′(h):X′(B)→\mathsf{X}'(h) :\mathsf{X}'(B)\rightarrow X′(A)\mathsf{X}'(A) is continuous. If hh is surjective, X′(h)\mathsf{X}'(h) is a homeomorphism of X′(B)\mathsf{X}'(B) onto its image, and this image is closed in X′(A)\mathsf{X}'(A).

Let A=A1×⋯×AnA = A_1\times \cdots \times A_n; with the same notation as above, X′(πi)\mathsf{X}'(\pi_i) is a homeomorphism of X′(Ai)\mathsf{X}'(A_i) onto Xi′\mathsf{X}'_i and Xi′\mathsf{X}'_i is closed in X′(A)\mathsf{X}'(A). Hence Xi′−{0}\mathsf{X}'_i-\{0\} is open in X′(A)\mathsf{X}'(A); the X′(πi)\mathsf{X}'(\pi_i) define a continuous mapping of the sum space S of the X′(Ai)\mathsf{X}'(A_i) onto X′(A)\mathsf{X}'(A), and one immediately verifies that a union of neighbourhoods of the points 0∈X′(A1),...,0∈X′(An)0\in \mathsf{X}'(A_1), . . . ,0\in \mathsf{X}'(A_n) has for image a neighbourhood of 0∈X′(A)0\in \mathsf{X}'(A); from all this it follows that X′(A)\mathsf{X}'(A) is canonically identified with a quotient space of S. In particular, the space X(A)\mathsf{X}(A) is identified with the sum space of the X(Ai)\mathsf{X}(A_i).

The canonical bijection of X′(A)\mathsf{X}'(A) onto X(A~)\mathsf{X}(\widetilde{A}) is a homeomorphism. Let B be a unital algebra over K and B′B' the underlying algebra; then the space X(B)\mathsf{X}(B) is identified with the subspace X(B′)\mathsf{X}(B') of X′(B′)\mathsf{X}'(B').

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.