Bourbaki

Lemma 6

Tag 02A3, permanent. Cite it as [Bourbaki, Tag 02A3].

Théories spectrales, chapter I, § 4. Calcul fonctionnel holomorphe

Let a∈An\boldsymbol{a}\in A^n. All sequences adapted to a\boldsymbol{a} are linked.

Let (h,u1,...,un)(h, u_1, . . . , u_n) and (h′,u1′,...,un′)(h', u'_1, . . . , u'_n) be sequences adapted to a\boldsymbol{a}, and let us denote by ω\omega and ω′\omega ' the associated differential forms.

Define the indefinitely differentiable mappings

wij=ui′uj−uiuj′,1⩽i⩽n,1⩽j⩽n w_{ij}=u'_iu_j-u_iu'_j,1\leqslant i\leqslant n,1\leqslant j\leqslant n
si=ui′h−uih′,1⩽i⩽n s_i=u'_ih-u_ih',1\leqslant i\leqslant n

so that wji=−wijw_{ji}=-w_{ij}, and Supp(sis_i)⊂\subset Supp(hh)∪\cup Supp(h′h').

Let ui′′=ui′−si,u=(u1,...,un)u''_i=u'_i-s_i,\boldsymbol{u}= (u_1, . . . , u_n) and u′′=(u1′′,...,un′′)\boldsymbol{u}''= (u''_1, . . . , u''_n). Let us also denote by vij\boldsymbol{v}_{ij} the mapping of Cn\mathbf{C}^n into AnA^n whose ii-th component is (zj−aj)wij(z_j-a_j)w_{ij}, whose jj-th component is (zi−ai)wji=−(zi−ai)wij(z_i-a_i)w_{ji}=-(z_i-a_i)w_{ij}, and whose other components are zero. Then we have

u′′=u+∑i<jvij \boldsymbol{u}''=\boldsymbol{u}+\sum_{i<j}\boldsymbol{v}_{ij}

In fact, for every integer kk such that 1⩽k⩽n1\leqslant k\leqslant n, the kk-th component of the right-hand side is

uk+∑i=1k−1(zi−ai)wki+∑j=k+1n(zj−aj)wkj=uk+∑i=1n(zi−ai)wki u_k+\sum^{k-1}_{i=1}(z_i-a_i)w_{ki}+\sum_{j=k+1}^n(z_j-a_j)w_{kj}=u_k+\sum_{i=1}^n(z_i-a_i)w_{ki}
=uk+uk′∑i=1n(zi−ai)ui−uk∑i=1n(zi−ai)ui′ =u_k+u'_k\sum_{i=1}^n(z_i-a_i)u_i-u_k\sum_{i=1}^n(z_i-a_i)u'_i
=uk+(1−h)uk′−(1−h′)uk=uk′−sk =u_k+ (1-h)u'_k-(1-h')u_k=u'_k-s_k

By induction, one deduces from Lemma 5, applied to the integers ii and jj and to the mappings wijw_{ij}, that the sequence (h,u1′′,...,un′′)(h, u''_1, . . . , u''_n) is adapted to a\boldsymbol{a} and is linked to (h,u1,...,un)(h, u_1, . . . , u_n). Let ω′′\omega '' be the differential form associated with (h,u1′′,...,un′′)(h, u''_1, . . . , u''_n). Since ui′′=ui′−siu''_i=u'_i-s_i, we have

ω′′−ω′=d(u1′−s1)∧dz1∧⋯∧d(un′−sn)∧dzn− \omega ''-\omega '=d(u'_1-s_1)\wedge dz_1\wedge \cdots \wedge d(u'_n-s_n)\wedge dz_n-
du1′∧dz1∧⋯∧dun′∧dzn du'_1\wedge dz_1\wedge \cdots \wedge du'_n\wedge dz_n

which is expressed as a linear combination, with coefficients 1 or −1-1, of differential forms of the form

ξI1,I2=⋀i∈I1dsi∧⋀i∈I2dui′∧dz1∧⋯∧dzn \xi_{I_1,I_2}=\bigwedge_{i\in I_1}ds_i\wedge \bigwedge_{i\in I_2}du'_i\wedge dz_1\wedge \cdots \wedge dz_n

where I1I_1 (resp. I2I_2) is a nonempty subset (resp. a subset) of {1,...,n}\{1, . . . , n\}. Each differential form ξI1,I2\xi_{I_1,I_2} can also be written in the form

d(ψ~∧dz1∧⋯∧dzn) d(\widetilde{\psi}\wedge dz_1\wedge \cdots \wedge dz_n)

where the support of the differential form ψ~\widetilde{\psi} is contained in the support of sis_i for every i∈I1i\in I_1. Since I1I_1 is nonempty, this support is contained in Supp(hh)∪\cup Supp(h′h'). Consequently, (h,u1′′,...,un′′)(h, u''_1, . . . , u''_n) is linked to (h′,u1′,...,un′)(h', u'_1, . . . , u'_n), and the lemma results on writing

ω−ω′=(ω−ω′′)+(ω′′−ω′) \omega -\omega '= (\omega -\omega '') + (\omega ''-\omega ')

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5-6-mini, gpt-5-mini, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.