Let (h,u1,...,un) and (h′,u1′,...,un′) be sequences adapted to a, and let us denote by ω and ω′ the associated differential forms.
Define the indefinitely differentiable mappings
wij=ui′uj−uiuj′,1⩽i⩽n,1⩽j⩽n
si=ui′h−uih′,1⩽i⩽n
so that wji=−wij, and Supp(si)⊂ Supp(h)∪ Supp(h′).
Let ui′′=ui′−si,u=(u1,...,un) and u′′=(u1′′,...,un′′). Let us also denote by vij the mapping of Cn into An whose i-th component is (zj−aj)wij, whose j-th component is (zi−ai)wji=−(zi−ai)wij, and whose other components are zero. Then we have
u′′=u+i<j∑vij
In fact, for every integer k such that 1⩽k⩽n, the k-th component of the right-hand side is
By induction, one deduces from Lemma 5, applied to the integers i and j and to the mappings wij, that the sequence (h,u1′′,...,un′′) is adapted to a and is linked to (h,u1,...,un). Let ω′′ be the differential form associated with (h,u1′′,...,un′′). Since ui′′=ui′−si, we have
ω′′−ω′=d(u1′−s1)∧dz1∧⋯∧d(un′−sn)∧dzn−
du1′∧dz1∧⋯∧dun′∧dzn
which is expressed as a linear combination, with coefficients 1 or −1, of differential forms of the form
ξI1,I2=i∈I1⋀dsi∧i∈I2⋀dui′∧dz1∧⋯∧dzn
where I1 (resp. I2) is a nonempty subset (resp. a subset) of {1,...,n}. Each differential form ξI1,I2 can also be written in the form
d(ψ∧dz1∧⋯∧dzn)
where the support of the differential form ψ is contained in the support of si for every i∈I1. Since I1 is nonempty, this support is contained in Supp(h)∪ Supp(h′). Consequently, (h,u1′′,...,un′′) is linked to (h′,u1′,...,un′), and the lemma results on writing
ω−ω′=(ω−ω′′)+(ω′′−ω′)
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.