Bourbaki

Lemma 7

Tag 02A4, permanent. Cite it as [Bourbaki, Tag 02A4].

Théories spectrales, chapter I, § 4. Calcul fonctionnel holomorphe

For every function f∈O(U;A)f\in \mathscr{O}(U; A), the integral ∫Ufω\int_Uf \omega is an element of A depending only on a\boldsymbol{a} and on the germ of ff in a neighbourhood of Spn(a)^n(\boldsymbol{a}). It satisfies the inequality

(4) ∥∫fω∥⩽(∫∥ω∥)\|\int f \omega \|\leqslant (\int\|\omega \|) sup ∥f(z)∥\|f(z)\|,

U U z∈z\inSupp(hh)

and

∫U(af)ω=a∫Ufω \int_U(af)\omega =a\int_Uf \omega

for every a∈Aa\in A.

We have seen above that the integral is defined for f∈C(U;A)f\in \mathscr{C}(U; A) and satisfies

∥∫fω∥⩽∫∥f∥∥ω∥⩽(∫∥ω∥)\|\int f \omega \|\leqslant \int\|f\| \|\omega \|\leqslant (\int\|\omega \|) sup ∥f(z)∥\|f(z)\|.

U U U z∈z\inSupp(hh)

Moreover, for every a∈Aa\in A and every f∈C(U;A)f\in \mathscr{C}(U; A), we have

∫U(af)ω=a∫Ufω \int_U(af)\omega =a\int_Uf \omega

(INT, VI, §2, no2^o2, Prop. 2 applied to multiplication by aa).

Let (h′,u1′,...,un′)(h', u'_1, . . . , u'_n) be a sequence adapted to a\boldsymbol{a} such that Supp(h′h')⊂U\subset U. Let ω′\omega ' be the associated differential form. By Lemma 6 of I, p. 57, there exists a differential form ψ\psi on Cn\mathbf{C}^n of degree n−1n-1, with coefficients in A and with support contained in Supp(hh)∪\cup Supp(h′h')⊂U\subset U, such that

ω−ω′=d(ψ∧dz1∧⋯∧dzn) \omega -\omega '=d(\psi \wedge dz_1\wedge \cdots \wedge dz_n)

Let f∈O(U;A)f\in \mathscr{O}(U; A). Since the mapping ff is holomorphic, we have

df=∑n∂f∂zidzi df=\sum^n\frac{\partial f}{\partial z_i}dz_i
i=1i=1

(VAR, R2, p. 24, 8.8.9) and hence

f(ω−ω′)=fd(ψ∧dz1∧⋯∧dzn)=d(fψ∧dz1∧⋯∧dzn) f(\omega -\omega ') =f d(\psi \wedge dz_1\wedge \cdots \wedge dz_n) =d(f \psi \wedge dz_1\wedge \cdots \wedge dz_n)

By Stokes' formula (VAR, R2, p. 48, 11.2.3), we then have

∫Uf(ω−ω′)=0 \int_Uf(\omega -\omega ') = 0

Thus the element ∫Ufω\int_Uf \omega does not depend on the choice of the sequence (h,u1,...,un)(h, u_1, . . . , u_n).

To conclude, let us prove that ∫Ufω\int_Uf \omega depends only on the germ of ff in a neighbourhood of Spn(a)^n(\boldsymbol{a}). Let U and U′U' be open neighbourhoods of Spn(a)^n(\boldsymbol{a}). Let f∈O(U;A)f\in \mathscr{O}(U; A) and f′∈O(U′;A)f'\in \mathscr{O}(U'; A) be such that ff and f′f' coincide on an open neighbourhood U′′U'' of Spn(a)^n(\boldsymbol{a}). There exists a mapping hh of Cn\mathbf{C}^n into C\mathbf{C}, indefinitely differentiable, equal to 1 in a neighbourhood of Spn(a)^n(\boldsymbol{a}), and with compact support contained in U′′U'' (Lemma 1 of I, p. 52), and there exists (u1,...,un)(u_1, . . . , u_n) such that the sequence (h,u1,...,un)(h, u_1, . . . , u_n) is adapted to a\boldsymbol{a} (Lemma 3 of I, p. 54). Let ω\omega be the associated differential form. Since Supp(ω\omega )⊂\subset Supp(hh)⊂U′′\subset U'' (Lemma 4, b) of I, p. 54), we have

∫Ufω=∫U′′fω=∫U′′f′ω=∫U′f′ω \int_Uf \omega =\int_{U''}f \omega =\int_{U''}f'\omega =\int_{U'}f'\omega

which completes the proof.

This lemma proves that there exists a unique a-linear mapping Θa\Theta_{\boldsymbol{a}} of O\mathscr{O}(Spn(a);A^n(\boldsymbol{a}); A) into A such that

(5) Θa(f)=n\Theta_{\boldsymbol{a}}(f) =n! n∫fω~_n\int\widetilde{f \omega}

(2iπ)U (2i\pi )_U

for every open set U and every representative f~∈O(U;A)\widetilde{f}\in \mathscr{O}(U; A) of a germ f∈Of\in \mathscr{O}(Spn(a);A^n(\boldsymbol{a}); A). The linear mapping Θa\Theta_{\boldsymbol{a}} is continuous by inequality (4) and EVT, II, p. 29, Proposition 5.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5-6-mini, gpt-5-mini, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.