Bourbaki

Proposition 17

Tag 02B5, permanent. Cite it as [Bourbaki, Tag 02B5].

Théories spectrales, chapter I, § 4. Calcul fonctionnel holomorphe

Let μ\mu be an isolated point of SpA(x)_A(x). Then

a) For every λ∈C−\lambda \in \mathbf{C}- SpA(x)_A(x), we have

R(x,λ)=R{μ}(x,λ)+RSpA(x)−{μ}(x,λ)R(x, \lambda ) = R_{\{\mu\}}(x, \lambda ) + R_{Sp_A(x)-\{\mu\}}(x, \lambda ) ;

b) The function which associates to λ\lambda RSpA(x)−{μ}(x,λ)R_{Sp_A(x)-\{\mu\}}(x, \lambda ) is holomorphic in C−\mathbf{C}- SpA(x)_A(x) and in a neighbourhood of μ\mu; moreover, the function which associates to λ\lambda R{μ}(x,λ)R_{\{\mu\}}(x, \lambda ) is holomorphic in C−{μ}\mathbf{C}-\{\mu\};

c) One has

limn→+∞∥(x−μ)nj{μ}∥1/n=0_{n\rightarrow+\infty}\|(x-\mu)^nj_{\{\mu\}}\|^{1/n}= 0

and, for λ∈C−{μ}\lambda \in \mathbf{C}-\{\mu\}, the formula

R{μ}(x,λ)=∑n=0∞(λ−μ)−n−1(x−μ)nj{μ}(20) R_{\{\mu\}}(x, \lambda ) =\sum_{n=0}^{\infty}(\lambda -\mu)^{-n-1}(x-\mu)^nj_{\{\mu\}} \tag{20}

The foregoing implies assertions a) and b). Let us prove c). Replacing xx by x−μx-\mu, we are reduced to the case where μ=0\mu= 0. Put H={0}H =\{0\}; this is an open and closed subset of SpA(x)_A(x). By formula (18), the spectrum of xHx_H in AHA_H is {0}\{0\}, hence xHx_H is quasi-nilpotent, that is to say, ∥xnjH∥1/n=∥(xjH)n∥1/n\|x^nj_H\|^{1/n}=\|(xj_H)^n\|^{1/n} tends to 0 as nn tends to +∞+\infty. Moreover, for λ≠0\lambda \not= 0, one has in AHA_H

(λjH−xH)−1=∑n=0∞λ−n−1xHn (\lambda j_H-x_H)^{-1}=\sum_{n=0}^{\infty}\lambda^{-n-1}x^n_H

(Theorem 1 of I, p. 24, d)), whence (20).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Machine translation of the English, by gpt-5-6-mini, gpt-5-mini, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.