Bourbaki

Corollary 2

Tag 02B7, permanent. Cite it as [Bourbaki, Tag 02B7].

Théories spectrales, chapter I, § 4. Calcul fonctionnel holomorphe

Let μ\mu be an isolated point of SpA(x)_A(x). Let Γ be the oriented boundary of an open disk Δ with center μ\mu such that

SpA(x)∩(Γ∪Δ)={μ}_A(x)\cap (\Gamma \cup \Delta ) =\{\mu\}.

Then the idempotent j{μ}j_{\{\mu\}} associated with xx and {μ}\{\mu\} is given by

j{μ}=12iπ∫Γ(z−x)−1dz j_{\{\mu\}}=\frac{1}{2i\pi}\int_{\Gamma}(z-x)^{-1}dz

*In other words, the idempotent j{μ}j_{\{\mu\}} is the residue at μ\mu of the resolvent of x.∗x.*

For z∈C−z\in \mathbf{C}- SpA(x)_A(x), one has

(z−u)−1=R(x,z)=R{μ}(x,z)+RH(x,z) (z-u)^{-1}= R(x, z) = R_{\{\mu\}}(x, z) + R_H(x, z)

where H = SpA(x)−{μ}_A(x)-\{\mu\} (formula (19)). The function z↦RH(x,z)z\mapsto R_H(x, z) is holomorphic in C−\mathbf{C}- H and in a neighbourhood of {μ}\{\mu\} (Prop. 17, b)), hence

12iπ∫ΓRH(x,z)dz=0 \frac{1}{2i\pi}\int_{\Gamma}R_H(x, z)dz= 0

(VAR, R2, p. 48, 11.2.5). The function z↦R{λ}(x,z)z\mapsto R_{\{\lambda\}}(x, z) is the resolvent of the element j{μ}xj{μ}j_{\{\mu\}}xj_{\{\mu\}} of the unital algebra A{μ}A_{\{\mu\}}. One then has

j{μ}=12iπ∫ΓR{μ}(x,z)dz j_{\{\mu\}}=\frac{1}{2i\pi}\int_{\Gamma}R_{\{\mu\}}(x, z)dz

by Prop. 9 of I, p. 75 applied to A{μ}A_{\{\mu\}} and to the constant function 1 in a neighbourhood of Δ∪Γ\Delta \cup \Gamma. The corollary follows.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5-6-mini, gpt-5-mini, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.