For every f∈O(SpA(C)(x)), one has f∗(1⊗x)=f(1⊗x).
The mappings f↦f(1⊗x) and f↦f∗(1⊗x) are continuous unital homomorphisms of C-algebras from O(Sp(x)) into A(C) which map z to 1⊗x; they are therefore equal (I, p. 74, th. 5).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.