Bourbaki

Proposition 20

Tag 02BC, permanent. Cite it as [Bourbaki, Tag 02BC].

Théories spectrales, chapter I, § 4. Calcul fonctionnel holomorphe

For every f∈ORf\in \mathscr{O}_{\mathbf{R}}(SpA(C)(x)_{A_{(\mathbf{C})}}(x)), there exists a unique element f(x)f(x) of A such that f(1⊗x)=1⊗f(x)f(1\otimes x) = 1\otimes f(x) in A(C)A_{(\mathbf{C})}. The mapping f↦f(x)f\mapsto f(x) from OR\mathscr{O}_{\mathbf{R}}(SpA(C)(x)_{A_{(\mathbf{C})}}(x)) into A is the unique continuous unital homomorphism of R\mathbf{R}-algebras which maps to xx the germ in OR\mathscr{O}_{\mathbf{R}}(SpA(C)(x)_{A_{(\mathbf{C})}}(x)) of the identical mapping of C\mathbf{C}.

Let us put S = SpA(C)(x)_{A_{(\mathbf{C})}}(x). By the above lemma, for every germ f∈ORf\in \mathscr{O}_{\mathbf{R}}(Sp(xx)), one has f(1⊗x)=f(1⊗x)‾f(1\otimes x) =\overline{f(1 \otimes x)}. The first assertion follows from this. Let us denote by zz the germ in OR(S)\mathscr{O}_{\mathbf{R}}(S) of the identical mapping of C\mathbf{C}. The mapping f↦f(x)f\mapsto f(x) is a continuous unital homomorphism of the R\mathbf{R}-algebra OR\mathscr{O}_{\mathbf{R}}(Sp(xx)) into A, which maps zz to xx. It is the only one by prop. 19, since every morphism having these properties is uniquely determined on every full closed sub-R\mathbf{R}-algebra of O(S)\mathscr{O}(S) containing zz.

Let f∈ORf\in \mathscr{O}_{\mathbf{R}}(SpA(C)(x)_{A_{(\mathbf{C})}}(x)). The element f(x)f(x) belongs to every full closed subalgebra of A containing xx (prop. 19), and therefore belongs to the bicommutant of xx in A. The complex spectrum of f(x)f(x) is equal to ff(Sp(xx)) (I, p. 75, prop. 8). For every g∈OR(fg\in \mathscr{O}_{\mathbf{R}}(f(SpA(C)(x)_{A_{(\mathbf{C})}}(x))), one has g∘f∈ORg\circ f\in \mathscr{O}_{\mathbf{R}}(SpA(C)(x)_{A_{(\mathbf{C})}}(x)) and (loc. cit.) (g∘f)(x)=g(f(x))(g\circ f)(x) =g(f(x)).

Let U be an open subset of C\mathbf{C}, stable under complex conjugation. The set Ω of elements xx of A whose complex spectrum is contained in U is open in A (I, p. 76, Prop. 10). Let ff be a holomorphic function on U such that f∗=ff^*=f. The mapping x↦f(x)x\mapsto f(x) of Ω into A is analytic (loc. cit.).

Let A, B be complete normable unital associative algebras over R\mathbf{R} and let φ:A→\varphi : A\rightarrow B be a continuous unital algebra morphism. Let x∈Ax\in A. The complex spectrum of φ(x)\varphi (x) is contained in that of xx and, for every f∈ORf\in \mathscr{O}_{\mathbf{R}}(SpA(C)(x)_{A_{(\mathbf{C})}}(x)), one has f(φ(x))=φ(f(x))f(\varphi (x)) =\varphi (f(x)). This results at once from the analogous statement in the complex case (I, p. 75, Prop. 8).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5-6-mini, gpt-5-mini, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.