Spectral Theories, II, p. 296
a) Let H⊂C be the open set of complex numbers z such that I(z)>0. The function
Θ(z)=n∈Z∑e2iπn2z
is holomorphic on H, and it satisfies Θ(z)=(z/i)−1/2Θ(−1/z) for z∈H, where z↦(z/i)1/2 is the unique holomorphic function on H which extends the function
iy↦y. (Use Exercise 16, b).)
b) Let m and n be strictly positive integers. One has
√1m∑m−1e2iπk2n/m=e√iπ/2n∑42n−1e−2iπk2m/(2n)
k=0k=0
(Apply the relation of the preceding question with z=−2in/m+iy and let y→0.) c) For every integer m⩾1 and every n∈Z, put
τ(n,m)=k=0∑m−1e2iπk2n/m
For all strictly positive integers m1 and m2, one has
τ(1,m1m2)=τ(m2,m1)τ(m1,m2)
((m−1)/2)2√
d) If m is odd, one has τ(1,m)=im. (Use a).)
e) If p is an odd prime number, then τ(n,p)=ℓp(n)τ(1,p), where ℓp is the unique character of order 2 of (Z/pZ)∗, extended to Z/pZ by putting ℓp(0)=0.
f) Let p=q be two odd prime numbers. One has
ℓp(q)ℓq(p)=τ(1,p)τ(1,q)τ(1,pq)
g) Deduce a new proof of the quadratic reciprocity law (cf. A, V, p. 156, exerc. 23): for all odd prime numbers p=q, one has
ℓp(q)ℓq(p)=(−1)(p−1)(q−1)/4
Nothing.
Nothing.