Bourbaki

Exercise 8, § 2

Tag 03BK, permanent. Cite it as [Bourbaki, Tag 03BK].

Spectral Theories, V, p. 487

Bourbaki marks this one as harder than the rest.

Suppose that G is a unimodular locally compact group. Let Γ be a discrete subgroup of G such that the quotient space X=Γ\GX = \Gamma \backslash G is compact. Let μ\mu be a Haar measure on G and β\beta the counting measure on Γ; write μ~=μ/β\widetilde{\mu}=\mu/\beta.

Let ϱ\varrho be the unitary representation of G on L2(X,μ~)L^2(X,\widetilde{\mu}) defined in example 3 of V, p. 404.

For γ∈Γ\gamma \in \Gamma, write Γγ\Gamma_{\gamma} (resp. GγG_{\gamma}) for the centralizer of γ\gamma in Γ (resp. G). a) The group GγG_{\gamma} is unimodular.

b) Let φ∈K(G)\varphi \in \mathscr{K}(G). For every Γ-automorphic unitary representation π\pi, the endomorphism π(φ)\pi (\varphi ) is of finite trace.

c) One has

Tr(ϱ(φ)\varrho (\varphi )) =∑π∈G^mπ(ϱ)=\sum_{\pi\in\widehat{G}}m_{\pi}(\varrho ) Tr(π(φ)\pi (\varphi ))

where mπ(ϱ)m_{\pi}(\varrho ) is the multiplicity of π\pi in ϱ\varrho ("spectral side of the trace formula").

d) Let Γ♯\Gamma^{\sharp} be the set of conjugacy classes of Γ. For γ∈Γ♯\gamma \in \Gamma^{\sharp}, write βγ\beta_{\gamma} for the counting measure on Γγ\Gamma_{\gamma}. One has

Tr(ϱ(φ)\varrho (\varphi )) =∑∫φ(x−1γx)d(μ/βγ)(x)=\sum\int\varphi (x^{-1}\gamma x)d(\mu/\beta_{\gamma})(x).

♯Γγ\G _{\sharp}\Gamma_{\gamma}\backslash G
γ∈Γ\gamma \in \Gamma

e) Fix a Haar measure μγ\mu_{\gamma} on GγG_{\gamma} for every γ∈Γ\gamma \in \Gamma. One has

Tr(ϱ(φ)\varrho (\varphi )) =∑∫∫φ(x−1y−1γyx)d(μγ/βγ)(y)d(μ/μγ)(x)=\sum\int\int\varphi (x^{-1}y^{-1}\gamma yx)d(\mu_{\gamma}/\beta_{\gamma})(y)d(\mu/\mu_{\gamma})(x).

∈♯Gγ\GΓγ\Gγ\in^{\sharp}G_{\gamma}\backslash G\Gamma_{\gamma}\backslash G_{\gamma} γ\gamma Γ

f) For every γ∈Γ\gamma \in \Gamma, the quotient measure μγ/βγ\mu_{\gamma}/\beta_{\gamma} of Γγ\Gγ\Gamma_{\gamma}\backslash G_{\gamma} is finite. g) One has

Tr(ϱ(φ)\varrho (\varphi )) =∑(μγ/βγ)(Γγ\Gγ)∫φ(x−1γx)d(μ/μγ)(x)=\sum(\mu_{\gamma}/\beta_{\gamma})(\Gamma_{\gamma}\backslash G_{\gamma})\int\varphi (x^{-1}\gamma x)d(\mu/\mu_{\gamma})(x)

∈♯Gγ\G\in^{\sharp}G_{\gamma}\backslash G γ\gamma Γ

("geometric side of the trace formula"; the formula expressing the equality of this expression with that obtained in question c) is called the "trace formula" for Γ-automorphic representations).

h) Put G=RG =\mathbf{R} and Γ=Z\Gamma =\mathbf{Z}. Verify that the trace formula is equivalent in this case to Poisson's formula (cf. II, p. 239).

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Machine translation of the English, by gpt-5.4. Not checked by a person.