Bourbaki

Proposition 1

Tag 03IJ, permanent. Cite it as [Bourbaki, Tag 03IJ].

Theory of Sets, chapter II, § 5. Product of a family of sets

(1) If ff is a surjection of a set E onto a set F, the canonical extension f^\hat{f} of ff is a surjection of P(E)\mathfrak{P}(\mathrm{E}) onto P(F)\mathfrak{P}(\mathrm{F}).

(2) If ff is an injection of E into F, the canonical extension f^\hat{f} of ff is an injection of P(E)\mathfrak{P}(\mathrm{E}) into P(F)\mathfrak{P}(\mathrm{F}).

(1) If ss is a section of ff, then f∘sf \circ s is the identity mapping of F, hence f^∘s^\hat{f} \circ \hat{s} is the identity mapping of P(F)\mathfrak{P}(\mathrm{F}); therefore f^\hat{f} is surjective and s^\hat{s} is a section of f^\hat{f} (§3, no. 8).

(2) The proposition is obvious if E=∅E = \varnothing, because then P(E)={∅}\mathfrak{P}(E) = \{\varnothing\}. If E≠∅E \ne \varnothing and if rr is a retraction of ff, then r∘fr \circ f is the identity mapping of EE, so that r^∘f^\hat{r} \circ \hat{f} is the identity mapping of P(E)\mathfrak{P}(E); therefore f^\hat{f} is injective, and r^\hat{r} is a retraction of f^\hat{f} (§3, no. 8).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2004, Springer. Not translated.