Bourbaki

Definition 6

Tag 03Q0, permanent. Cite it as [Bourbaki, Tag 03Q0].

Theory of Sets, chapter II, § 4. Union and intersection of a family of sets

Two sets A and B are said to be disjoint (or not to intersect) if A∩B=∅A \cap B = \emptyset. If A∩B≠∅A \cap B \neq \emptyset, we say that A meets (or intersects) B. Let (Xι)ι∈I(\mathrm{X}_\iota)_{\iota \in \mathrm{I}} be a family of sets. The sets of this family are said to be mutually disjoint if the conditions ι∈I\iota \in \mathrm{I}, ϰ∈I\varkappa \in \mathrm{I}, ι≠ϰ\iota \neq \varkappa imply Xι∩Xϰ=∅\mathrm{X}_\iota \cap \mathrm{X}_\varkappa = \emptyset.

Let ff be a mapping of A into B, and let (Yι)ι∈I(\mathrm{Y}_\iota)_{\iota \in \mathrm{I}} be a family of mutually disjoint subsets of B. Proposition 4 then shows that the sets of the family (f−1⟨Yι⟩)ι∈I(\overset{-1}{f}\langle \mathrm{Y}_\iota \rangle)_{\iota \in \mathrm{I}} of subsets of A are mutually disjoint. On the other hand, if (Xι)ι∈I(\mathrm{X}_\iota)_{\iota \in \mathrm{I}} is a family of mutually disjoint subsets of A, the sets of the family (f⟨Xι⟩)ι∈I(f \langle \mathrm{X}_\iota \rangle)_{\iota \in \mathrm{I}} are not in general mutually disjoint.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 2004, Springer. Not translated.