Bourbaki

Proposition 10

Tag 03QL, permanent. Cite it as [Bourbaki, Tag 03QL].

Theory of Sets, chapter III, § 1. Order relations. Ordered sets

In a right directed ordered set E, a maximal element a is the greatest element of E.

For every x∈Ex \in \mathrm{E} there exists by hypothesis y∈Ey \in \mathrm{E} such that x⩽yx \leqslant y and a⩽ya \leqslant y; since aa is maximal, y=ay = a.

¶ A right directed preordered set is left directed with respect to the opposite ordering. Any product of right directed sets is right directed. On the other hand, a subset of a right directed set is not necessarily right directed. However, a cofinal subset F of a right directed set E is always right directed; for given xx, y∈Fy \in \mathrm{F} there exists z∈Ez \in \mathrm{E} such that x⩽zx \leqslant z and y⩽zy \leqslant z, and then t∈Ft \in \mathrm{F} such that z⩽tz \leqslant t.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

Nothing.

Transcribed from the printed edition, 2004, Springer. Not translated.