Theorem 1 (Zermelo)
Tag 03QS, permanent. Cite it as [Bourbaki, Tag 03QS].
Theory of Sets, chapter III, § 2. Well-ordered sets
Every set E can be well-ordered.
Let be the set of all subsets of E other than E itself. For each let ; since the relation implies , we have (Chapter I, § 4, no. 1) and therefore . We may therefore apply Lemma 3, and consequently there exists a well-ordering on a subset M of E such that ; but the only subset of E which does not belong to is E itself, and the theorem is proved.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
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