Bourbaki

Example 2

Tag 03TN, permanent. Cite it as [Bourbaki, Tag 03TN].

Theory of Sets, chapter III, § 7. Inverse limits and direct limits

Suppose that, for each α∈I\alpha \in \mathrm{I}, Eα\mathrm{E}_\alpha is the same set F and that whenever α⩽β\alpha \leqslant \beta, fβαf_{\beta\alpha} is the identity mapping of F onto itself. Then there exists a canonical bijection of lim→⁡Eα\varinjlim \mathrm{E}_\alpha onto F. In order to define lim→⁡Eα\varinjlim \mathrm{E}_\alpha, we have to form the set G which is the sum of the family (Eα)(\mathrm{E}_\alpha); G is therefore the union of a family (Gα)(\mathrm{G}_\alpha) of mutually disjoint sets, and for each α∈I\alpha \in \mathrm{I} there is a canonical bijection hα:F→Gαh_\alpha : \mathrm{F} \to \mathrm{G}_\alpha. We have next to consider the equivalence relation R on G corresponding to the partition (Py)y∈F(\mathrm{P}_y)_{y \in \mathrm{F}}, where Py\mathrm{P}_y is the set of all hα(y)h_\alpha(y) as α\alpha runs through I. Clearly y→Pyy \to \mathrm{P}_y is a bijection whose inverse is the bijection required. We shall identify F with lim→⁡Eα\varinjlim \mathrm{E}_\alpha by means of this canonical bijection.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2004, Springer. Not translated.