Bourbaki

Exercise 23, § 1

Tag 03UJ, permanent. Cite it as [Bourbaki, Tag 03UJ].

Theory of Sets, III, 220

Bourbaki marks this one as harder than the rest.

Let E be an ordered set and let R0(E)=R(E)−{∅}R_0(E) = R(E) - \{\emptyset\} (Exercise 22). For each x∈Ex \in E, let r(x)r(x) denote the unique regular open set in which the interval [x,→[[x, \rightarrow[ (which is an open set) is cofinal. The mapping rr so defined is called the canonical mapping of E into R0(E)R_0(E). Endow R0(E)R_0(E) with the order relation opposite to the relation of inclusion.

(a) Show that the mapping rr is increasing and that r(E)r(E) is cofinal in R0(E)R_0(E).

(b) An ordered set E is said to be antidirected if the canonical mapping r:E→R0(E)r : E \rightarrow R_0(E) is injective. For this to be so it is necessary and sufficient that the following two conditions should be satisfied :

(I) If xx and yy are two elements of E such that x<yx < y, there exists z∈Ez \in E such that x<zx < z and such that the intervals [y,→[[y, \rightarrow[ and [z,→[[z, \rightarrow[ do not intersect.

(II) If xx and yy are two non-comparable elements of E, then either there exists x′⩾xx' \geqslant x such that the intervals [x′,→[[x', \rightarrow[ and [y,→[[y, \rightarrow[ do not intersect, or else there exists y′⩾yy' \geqslant y such that the intervals [x,→[[x, \rightarrow[ and [y′,→[[y', \rightarrow[ do not intersect.

(c) Show that, for every ordered set E, R0(E)R_0(E) is antidirected and that the canonical mapping of R0(E)R_0(E) into R0(R0(E))R_0(R_0(E)) is bijective (use Exercise 22 (a)).

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