Bourbaki

Proposition 5

Tag 04BS, permanent. Cite it as [Bourbaki, Tag 04BS].

Commutative Algebra, chapter II, § 5. Finitely generated projective modules. Invertible fractional ideals

Let A be a semi-local ring and P a finitely generated projective A-module. If the rank of P is defined, P is a free A-module.

Suppose first that A is isomorphic to a product of fields KiK_i (1≤i≤n1 \leq i \leq n). The KiK_i are then identified with the minimal ideals (Algebra, Chapter VIII, § 3, no. 1) of A and, for all ii, the sum pip_i of the K, of index j≠ij \neq i is a maximal ideal of A, the pip_i (1≤i≤n1 \leq i \leq n) being the only prime ideals of A. Every finitely generated A-module P is therefore the direct sum of its isotypical components PiP_i (1≤i≤n1 \leq i \leq n), PiP_i being isomorphic to a direct sum of a finite number rir_i of A-modules isomorphic to K, (Algebra, Chapter VIII, § 5, no. 1, Proposition 1 and no. 3, Proposition 11); the ring AriA_{r_i} is identified with K, and annihilates the PjP_j of index j≠ij \neq i, hence ri=rgpi(P)r_i = \mathrm{rg}_{p_i}(P); if all the rir_i are equal to the same number rr, P is isomorphic to ArA^r, whence the proposition in this case. In the general case, let R\mathfrak{R} be the Jacobson radical of A and B=A/RB = A / \mathfrak{R}; as B is a product of fields, the projective B-module P(B)P_{(B)} is free by the remarks preceding Proposition 4. Also P is a flat A-module and the proposition then follows from § 3, no. 2, Proposition 5.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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