Bourbaki

Lemma 5

Tag 04OM, permanent. Cite it as [Bourbaki, Tag 04OM].

Commutative Algebra, chapter V, § 1. Notion of an integral element

*Let KK be a Noetherian ring, BB a finitely generated KK-algebra and CC a sub-K-algebra of B such that B is integral over C. Then C is a finitely generated A-algebra.

Let (xi)1≤i≤n(x_i)_{1 \leq i \leq n} be a finite system of generators of the K-algebra B. For all i, there exists by hypothesis a monic polynomial Pi∈C[X]P_i \in C[X] such that Pi(xi)=0P_i(x_i) = 0. Let C' be the sub-K-algebra of C generated by the coefficients of the PiP_i (1≤i≤n1 \leq i \leq n); clearly the xix_i are integral over C' and B=C′[x1,…,xn]B = C'[x_1, \ldots, x_n]; hence B is a finitely generated C'-module (no. 1, Proposition 4). On the other hand C′C' is a Noetherian ring (Chapter III, § 2, no. 10, Corollary 3 to Theorem 2); hence C is a finitely generated C′C'-module, which proves that C is a finitely generated K-algebra.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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