Bourbaki

Corollary

Tag 058W, permanent. Cite it as [Bourbaki, Tag 058W].

Algebra, chapter I, § 4. Groups and groups with operators

If G is a finite group of order g and H is a subgroup of G of order h, then

h⋅(G:H)=g h \cdot (G:H) = g
(in particular, the order and index of H are divisors of the order of G).

Theorem 1 allows us to determine the equivalence relations compatible with the laws on a group with operators G: if R is such a relation, it is both left and right compatible with the group law on G and with the action of Ω\Omega. Hence, if H is the class of ee (mod. R), H is a stable subgroup such that the relations y∈xHy \in xH and y∈Hxy \in Hx are equivalent (since both are equivalent to R); hence xH=HxxH = Hx for all x∈Gx \in G. Conversely, if this is so, one or other of the equivalent relations y∈xH,y∈Hxy \in xH, y \in Hx is compatible with the group law, since it is both left and right compatible with this law (§\S 3, no. 4) and is compatible with the action of Ω\Omega. Since the equation xH=HxxH = Hx is equivalent to xHx−1=HxHx^{-1} = H, we make the following definition:

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed edition, 1998, Springer. Not translated.