Example
Tag 05JX, permanent. Cite it as [Bourbaki, Tag 05JX].
Algebra, chapter II, § 1. Modules
(1) In any module the set consisting of 0 is a submodule (the zero submodule, often denoted by 0, by an abuse of notation). (2) Let be a ring. The submodules of (resp. ) are just the left ideals (resp. right ideals) of the ring . (3) Let be an -module, an element of and a left ideal of . The set of elements , where runs through , is a submodule of , denoted by . (4) In a commutative group considered as a -module (no. 1), every subgroup of is also a submodule.
(5) Let be an open interval of the real line ; the set of real-valued functions defined and continuous on is a vector subspace of the vector space of all real-valued functions defined on . Similarly, the set of differentiable functions on is a vector subspace of
Let be an -module. Every equivalence relation compatible (I, § 1, no. 6) with the module structure on is of the form , where is a stable subgroup of E (I, § 4, no. 4), that is a submodule of E. It is immediately verified that the structure of a group with operators on the quotient group E/M (I, § 4, no. 4) is an A-module structure, under which the canonical mapping is linear; with this structure, E/M is called the quotient module of E by the submodule M. A quotient module of a vector space E is called a quotient vector space (or simply quotient space) of E.
Example (6). Every left ideal in a ring A defines a quotient module of the left A-module ; by an abuse of notation, this quotient module is often denoted by .
Let E, F be two A-modules. It follows from the general properties of groups with operators (I, § 4, no. 5) (or directly from the definitions) that if is a linear mapping, the image under of any submodule of E is a submodule of F and the inverse image under of any submodule of F is a submodule of E. In particular, the kernel is a submodule of E and the image of E under is a submodule of F (I, § 4, no. 6, Proposition 7); by an abuse of language is called the image of u. The quotient module is also called the coimage of and the quotient module the cokernel of . In the canonical decomposition of (I, § 4, no. 5)
is an isomorphism of the coimage of onto the image of (no. 2, Proposition 2). For to be injective, it is necessary and sufficient that its kernel be zero; for to be surjective, it is necessary and sufficient that its cokernel be zero.
The kernel, image, coimage and cokernel of are denoted respectively by Ker , Im , Coim , Coker .
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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