Bourbaki

Proposition 12

Tag 0616, permanent. Cite it as [Bourbaki, Tag 0616].

Algebra, chapter III, § 4. Tensor products of algebras

("associativity" of the tensor ε\varepsilon-product of graded algebras of the same types). *With the notation of Proposition 10 of no. 7, suppose that all the Δi\Delta_i are equal to the same monoid Δ0\Delta_0; let (Jλ)λ∈L(J_\lambda)_{\lambda \in L} be a partition of I. With the notation of Proposition 11 of no. 7, suppose that the right hand side of formula (32) (no. 7) depends only on the sums αλ′′=∑i∈Jλαi,βμ′′=∑j∈Jμβj\alpha''_\lambda = \sum_{i \in J_\lambda} \alpha_i, \beta''_\mu = \sum_{j \in J_\mu} \beta_j, for every ordered pair (λ,μ)(\lambda, \mu) of distinct indices, all αλ′∈Δλ′\alpha'_\lambda \in \Delta'_\lambda and all βμ′∈Δμ′\beta'_\mu \in \Delta'_\mu; let ελμ′′(αλ′′,βμ′′)\varepsilon''_{\lambda \mu}(\alpha''_\lambda, \beta''_\mu) denote the right hand side of (32). *Then (ελμ′′)(\varepsilon''_{\lambda \mu}) is a system of commutation factors over the family (Δλ′′)λ∈L(\Delta''_\lambda)_{\lambda \in L}, where Δλ′′=Δ0\Delta''_\lambda = \Delta_0 for all λ∈L\lambda \in L. *If Eλ′′E''_\lambda is the graded tensor ε\varepsilon-product of type Δ0\Delta_0 of the family (Ei)i∈Jλ(E_i)_{i \in J_\lambda}, there exists one and only one isomorphism of graded algebras of type Δ0\Delta_0, w:ε′′⨂λ∈LEλ′′→ε⨂i∈IEiw : \varepsilon'' \bigotimes_{\lambda \in L} E''_\lambda \to \varepsilon \bigotimes_{i \in I} E_i, such that

w(⨂λ∈L(⨂i∈Jλxi))=⨂i∈Ixi w \left( \bigotimes_{\lambda \in L} \left( \bigotimes_{i \in J_\lambda} x_i \right) \right) = \bigotimes_{i \in I} x_i

provided that total orderings are chosen on the JλJ_\lambda and on I as described in no. 7, Proposition 11.

By the hypothesis, for γ,δ\gamma, \delta in Δ0\Delta_0, ελμ′′(γ,δ)=εi0j0(γ,δ)\varepsilon''_{\lambda \mu}(\gamma, \delta) = \varepsilon_{i_0 j_0}(\gamma, \delta) for some i0∈Jλi_0 \in J_\lambda and some j0∈Jμj_0 \in J_\mu, as is seen by considering the elements αλ′=(αi)i∈Jλ\alpha'_\lambda = (\alpha_i)_{i \in J_\lambda} and βμ′=(βj)j∈Jμ\beta'_\mu = (\beta_j)_{j \in J_\mu} such that αi0=γ,αi=0\alpha_{i_0} = \gamma, \alpha_i = 0 for i≠i0i \neq i_0, βj0=δ,βj=0\beta_{j_0} = \delta, \beta_j = 0 for j≠j0j \neq j_0; it follows immediately that the ελμ′′\varepsilon''_{\lambda \mu} form a system of commutation factors. The rest of the proof is then analogous to that of Proposition 11 (no. 7) and is left to the reader.

Note that the additional hypotheses of Proposition 12 are fulfilled when Δ0=Z\Delta_0 = \mathbf{Z} and that (εij)(\varepsilon_{ij}) is, either the trivial system of factors (εij(αi,βj))=1(\varepsilon_{ij}(\alpha_i, \beta_j)) = 1 for all i,ji, j, or the system of factors defined by εij(αi,βj)=(−1)αiβj\varepsilon_{ij}(\alpha_i, \beta_j) = (-1)^{\alpha_i \beta_j}; in the latter case, the right hand side of formula (32) is equal to (−1)γ(-1)^\gamma, where

γ=∑i∈Jλ,j∈Jμαiβj=(∑i∈Jλαi)(∑j∈Jμβj). \gamma = \sum_{i \in J_\lambda, j \in J_\mu} \alpha_i \beta_j = \left( \sum_{i \in J_\lambda} \alpha_i \right) \left( \sum_{j \in J_\mu} \beta_j \right).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 1998, Springer. Not translated.