Bourbaki

Remark 3

Tag 06SK, permanent. Cite it as [Bourbaki, Tag 06SK].

Algebra, V, p. 112, § 14. Transcendental extensions

It is clear that if E is algebraically disjoint from FF over K, when E and F are considered as subextensions of L, the same is true when they are considered as subextensions of K(E∪F)K(E \cup F) and conversely.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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Transcribed from the printed edition, 2003, Springer. Not translated.