Bourbaki

Remark 3

Tag 074J, permanent. Cite it as [Bourbaki, Tag 074J].

Algebra, VII, p. 25, § 4. Finitely generated modules over a principal ideal domain

To calculate the invariant factors of a torsion module whose elementary divisors are known, we again lean on the fact that, if the aia_i are pairwise coprime elements of AA, then the product ∏A/(ai)\prod A/(a_i) is a cyclic module isomorphic to A/(a1a2...an)A/(a_1 a_2 ... a_n) (VIIVII, p. 3, Prop. 4). Let us illustrate the method by looking at the example of the group G(464 600)=MG(464\ 600) = M: write the elementary divisors pnp^n of MM which are powers of the same irreducible pp on the same line, beginning with those of greatest exponent; extend these lines to lines of equal length by putting in 1's where necessary:

2222222525111111111. \begin{array}{cccccc} 2^2 & 2^2 & 2 & 2 & 2 \\ 5^2 & 5 & 1 & 1 & 1 \\ 11 & 1 & 1 & 1 & 1 . \end{array}

Then the invariant factors are the products of elements in the same column: 1100,20,2,2,21100, 20, 2, 2, 2. Indeed MM is isomorphic to a product of cyclic groups of orders 1100, 20, 2, 2, 2 by Prop. 4 of VIIVII, p. 3; since each of these orders is a multiple of the next, these are the invariant factors of MM (VIIVII, p. 22, Th. 3).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2003, Springer. Not translated.