Bourbaki

Proposition 3

Tag 07FR, permanent. Cite it as [Bourbaki, Tag 07FR].

Topological Vector Spaces, chapter II, § 5. Separation of convex sets

— In a topological vector space EE, let AA be a closed convex set with a non-empty interior. Then every support hyperplane of AA is closed and every frontier point of AA belongs to at least one support hyperplane of AA.

Every support hyperplane of AA is closed, since all the points of AA are on the same side of the hyperplane (II, p. 15, prop. 17). Also if x0x_0 is a frontier point of AA, then x0x_0 does not belong to the open non-empty convex set A∘\overset{\circ}{A}; after th. 1 of II, p. 36 there exists a hyperplane HH that contains x0x_0 and does not meet A∘\overset{\circ}{A}. As AA is the closure of A∘\overset{\circ}{A} (II, p. 14, cor. 1 to prop. 16), it follows from prop. 17 of II, p. 15 that HH is a support hyperplane of AA.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed volume. Not translated.