Bourbaki

Proposition 7

Tag 08QI, permanent. Cite it as [Bourbaki, Tag 08QI].

Integration, chapter IV, § 2. Negligible functions and sets

— If ff is a function ⩾0\geqslant 0 defined on XX such that ∣μ∣∗(f)<+∞|\mu|^*(f) < +\infty, then f(x)f(x) is finite almost everywhere.

For, let NN be the set of points x∈Xx \in X such that f(x)=+∞f(x) = +\infty; for every integer nn, nφN⩽fn \varphi_N \leqslant f, whence n∣μ∣∗(φN)⩽∣μ∣∗(f)n |\mu|^*(\varphi_N) \leqslant |\mu|^*(f); since nn is arbitrarily large, ∣μ∣∗(N)=0|\mu|^*(N) = 0.

However, even if XX is compact, a function f⩾0f \geqslant 0 defined on XX and everywhere finite can have infinite upper integral, as is shown by the example X=[0,1]X = [0, 1], f(x)=1/xf(x) = 1/x for x>0x > 0 and f(0)=0f(0) = 0, μ\mu being Lebesgue measure on XX.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Cites

Nothing.

Transcribed from the printed volume. Not translated.